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kogti [31]
4 years ago
7

A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?

Chemistry
2 answers:
Ahat [919]4 years ago
6 0

Answer:

                           O        H        C

Moles in 100g  3.33   6.65    3.33

Ratio                  1.00   2.00    1.00

Possible empirical formula = OH_{2}C

Oduvanchick [21]4 years ago
4 0

Answer:

CH2O

Explanation:

Data obtained from the question include:

C = 40%

H = 6.7%

O = 53.3%

Divide by their molar mass

C = 40/12 = 3.33

H = 6.7/1 = 6.7

O = 53.3/16 = 3.33

Divide by the smallest

C = 3.33/3.33 = 1

H = 6.7/3.33 = 2

O = 3.33/3.33 = 1

The empirical formula is CH2O

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Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

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Step 2: The balanced equation

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Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

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Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

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O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

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Step 6: Calculate mass ethane

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