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4 years ago

A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?

Chemistry

2 answers:

Ahat [919]4 years ago

6 0

Answer:

O H C

Moles in 100g 3.33 6.65 3.33

Ratio 1.00 2.00 1.00

Possible empirical formula = $OH_{2}C$

Oduvanchick [21]4 years ago

4 0

Answer:

CH2O

Explanation:

Data obtained from the question include:

C = 40%

H = 6.7%

O = 53.3%

Divide by their molar mass

C = 40/12 = 3.33

H = 6.7/1 = 6.7

O = 53.3/16 = 3.33

Divide by the smallest

C = 3.33/3.33 = 1

H = 6.7/3.33 = 2

O = 3.33/3.33 = 1

The empirical formula is CH2O

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3 years ago

A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea

Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

The mass of the oil in the cup, is approximately 64.73 grams.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The mass of oil in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

The mass of the oil in the cup, m₁ ≈ 64.73 g

Learn more here:

brainly.com/question/21406849

Possible part of the question obtained from a similar question online, are;

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating = 65.17°C

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3 years ago

the difference between these two measurements: 60 m and 60.00 m How many sig figs does each contain? Clearly explain which digit

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This problem is providing two measurements, 60 m and 60.00 m and asks for the difference in the significant digits, accuracy, uncertainty, whether they are the same or not and how they differ.

<h3>Significant figures:</h3>

In chemistry, the use of significant figures is crucial, because they define the most appropriate way to report a measurement. Thus, we can say that the more decimals a measurement has, the more accurate and the less uncertain it is. Also, if no decimal places are present, tracking zeros are not significant.

In such a way, one can conclude that 60 m has just one significant figure (0 does not count) whereas 60.00 m has four (there is a decimal making all zeros significant), 60.00 m is more accurate as more decimal places are reported. On the other hand 60 m is the more uncertain as less decimals contribute to its accuracy.

In addition, we say they can be the same measurement, as long as they represent the same idea, sixty meters, the thing is 60.00 m is more accurate yet they refer to the same measurement.

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