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2 years ago

Your flight takes you in the path of a large aircraft. in order to avoid the vortices you should fly

1 answer:

4 0

your flight takes you in the path of a large aircraft. in order to avoid the vortices, you should fly above the flight path of the large aircraft.

<h3>What is Vortex?</h3>

A vortex is an area in a fluid where the flow spins around an axis line, which may be straight or curved, according to the principles of fluid dynamics.
Smoke rings, whirlpools in a boat's wake, and the winds surrounding a tropical cyclone, tornado, or dust devil are examples of vortices that form in agitated fluids.
A significant element of turbulent flow is vortices. Vortices are defined by the distribution of velocity, vorticity (the curl of the flow velocity), and the idea of circulation.
The fluid flow velocity in most vortices is the highest close to the axis and drops in inverse proportion to the distance from the axis.

To learn more about vortex with the given link

brainly.com/question/14362952

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A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50

Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s we obtain

$T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2} }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\ 0=(\frac{4\pi^{2} }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2} }{3g} )\\ 4.03x^{2}-23.04x+0.335=0$

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0

4 years ago

Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min

Paha777 [63]

Answer: The correct answer is option (A).

Explanation:

Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

$P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s$

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:

$P_1=P_2$

$0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2$

$v_2=1 m/s$

Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.

4 0

4 years ago

You push a piano 5 meters across the floor with a force of 400 n. how much work have you done?

kobusy [5.1K]

2,000 j(apex)

i hope this was right

3 0

4 years ago

A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s 2 . What is the mass of the box?

kow [346]

Used Mephyso for the calculation