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2 years ago

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An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In o

ther words, what are the magnitudes of the components of the ship’s displacement vector in the north and the east direction, respectively?

1 answer:

Monica [59]2 years ago

6 0

I’m sorry if i took up a lot of space, hope this is a valid approximate answer

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According to the law of conservation of charge in alpha decay the total number of protons on one side of the equation equals the

Artyom0805 [142]

Answer:

True

Explanation:

For any equation to be balanced, be it elemental equation or radioactive decay equation, the number of atoms on the left must balance the number of atoms of the right. The same is true for alpha decay as the number of protons on the left side must equal the number of protons on the right side?

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3 years ago

iren2701 [21]

Answer:

idk ha ha ha

Explanation:

7 0

3 years ago

Blow up a balloon and rub it against your shirt a number of times. In doing so you give the balloon a net electric charge. Now t

tamaranim1 [39]

<span>Balloons are blown up, and then rubbed against your shirt many times. The balloon then touches the ceiling. When released, the balloon remains stuck to the ceiling. The balloon is charged by contact. The ceiling has a neutral charge. The charged balloon induces a slight surface charge on the ceiling opposite to the charge on the balloon. Balloon and ceiling electric charges are opposite in sign, so they will attract each other. Since both the balloon and the ceiling are insulators, charge can not flow from one to the other. The charge on the balloon is fixed on the balloon and the charge on the ceiling remains fixed to the ceiling. It just so happens that the<span> electrostatic force the ceiling exerts on the balloon is sufficient to hold the balloon in place (i.e. overcomes gravity, etc.).</span></span>

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3 years ago

You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget

aleksklad [387]

Answer:

35.7 m

Explanation:

Let

$\mid A\mid=18.5 m$

$\mid B\mid=41 m$

We have to find the distance between Joe's and Karl'e tent.

$A_x=Acos\theta$

$A_y=Asin\theta$

Substitute the values then we get

$A_x=18.5cos23^{\circ}=17 m$

$A_y=18.5sin 23^{\circ}=7.2 m$

$B_x=41cos37.5^{\circ}=32.5 m$

$B_y=41sin37.5^{\circ}=-24.96 m$

Because vertical component of B lie in IV quadrant and y-inIV quadrant is negative.

By triangle addition of vector

$B=A+C$

$C=B-A$

$C_x=B_x-A_x=32.5-17=15.5 m$

$C_y=B_y-A_y=-24.96-7.2=-32.16\approx=-32.2 m$

$\mid C\mid=\sqrt{C^2_x+C^2_y}$

$\mid C\mid=\sqrt{(15.5)^2+(-32.2)^2}=35.7 m$

Hence, the distance between Joe's and Karl's tent=35.7 m

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3 years ago

PLEASE HURRYYYY!!!<br><br> Explain how you read measurements in a graduated cylinder?

fredd [130]

Answer:

Reading a Graduated Cylinder

Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.....

hope it helps....

5 0

1 year ago