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8090 [49]
2 years ago
14

An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In o

ther words, what are the magnitudes of the components of the ship’s displacement vector in the north and the east direction, respectively?
Physics
1 answer:
Monica [59]2 years ago
6 0
I’m sorry if i took up a lot of space, hope this is a valid approximate answer

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Heat always flows from a what place to a what place
Vera_Pavlovna [14]

Answer:

Heat is always the transfer of energy from an object at a higher temperature to an object at a lower temperature.

Explanation:

6 0
3 years ago
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True or false: seismographs from three locations are studied to calculate the epicenter of am earthquake
astraxan [27]
True........don't blame me if i'm wrong.<span />
7 0
3 years ago
Consider two isolated, charged conducting spheres: a large sphere and a second smaller sphere with a radius 6 times smaller than
Troyanec [42]

Let the bigger sphere be sphere 1 and the let the smaller sphere be sphere 2. Rest of the answer is in the picture.

4 0
3 years ago
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.
noname [10]

Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

Explanation:

From the question we are told that

   The radius of the inner conductor  is  r_1 = 1 \ mm =  0.001 \ m

    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

    The potential at the outer conductor is  V = 1.5 kV  =  1.5 *10^{3} \  V

Generally the capacitance per length of the capacitor like set up of the two conductors is

      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

Here \epsilon_o is the permitivity of free space with value  \epsilon_o =  8.85*10^{-12} C/(V \cdot m)

=>   C= \frac{2 *  3.142  * 8.85*10^{-12}  }{ ln [\frac{0.003}{0.001} ]}

=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

      \rho_l  =  C *  V

=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

3 0
3 years ago
in three situations, a briefly applied horizontal force changes the velocity of a hockey puck that slides over frictionless ice.
victus00 [196]

The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

F= \frac{mv}{t}

The force applied to an object increases with increases in the velocity of the object.

In the given diagram, the resultant velocity of the puck is calculated as follows;

Figure a:

\Delta v = v_f -v_i\\\\\Delta v = 5 - 6 = - 1 \ m/s

Figure b:

v = \sqrt{4^2 + 3^2} \\\\v = 5 \ m/s

Figure c:

\Delta v = 4 - (-2)\\\\\Delta v = 6 \ m/s

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.

Learn more here:brainly.com/question/19498865

4 0
3 years ago
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