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Kryger [21]
3 years ago
11

A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that

when placed in the field the sphere is in a static situation (all the forces on the sphere cancel). If the thread is horizontal, find the magnitude and direction of the electric field. The sphere has a mass of 0.018 kg and contains a charge of + 6.80 x 103 C. The tension in the thread is 6.57 x 10-2 N. Show your work and/or explain your reasoning. (20 pts)
Physics
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

E = 9.66\times 10^{-6} N/C

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

F = qE

so here the force is tension force on it

F = 6.57 \times 10^{-2} N

Q = 6.80 \times 10^3 C

now we have

6.57 \times 10^{-2} = (6.80 \times 10^3)E

E = 9.66\times 10^{-6} N/C

direction is Horizontal

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4 0
3 years ago
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I’m stuck on this problem, help is very appreciated!!
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Explanation:

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8 0
2 years ago
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What is pressure?
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Explanation:

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3 years ago
An electron at Earth's surface experiences a gravitational force of magnitude F=(9.11×10−31 kg)⋅(9.8 m/s2). Part A How far away
katrin [286]

Answer:

r = 5,085 m

Explanation:

The force exerted by on the surface of the Earth on an electron is its weight

          W = F = 9.11 10⁻³¹  9.8

          W = 8.9 10⁻³⁰ N

The electric force between an electron and a proton is given by Coulomb's Law

         Fe = k q₁ q₂ / r²

         Fe = - k q² / r²

They ask us that W = Fe

         W = k q² / r²

          r = √ k q² / W

Let's calculate

        r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰

        r = √ 25.86

        r = 5,085 m

Let's look for the relationship of this distance with the harmonic distance

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        R / R_Atomic = 5 10¹⁰

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8 0
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