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Kryger [21]
4 years ago
11

A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that

when placed in the field the sphere is in a static situation (all the forces on the sphere cancel). If the thread is horizontal, find the magnitude and direction of the electric field. The sphere has a mass of 0.018 kg and contains a charge of + 6.80 x 103 C. The tension in the thread is 6.57 x 10-2 N. Show your work and/or explain your reasoning. (20 pts)
Physics
1 answer:
VMariaS [17]4 years ago
4 0

Answer:

E = 9.66\times 10^{-6} N/C

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

F = qE

so here the force is tension force on it

F = 6.57 \times 10^{-2} N

Q = 6.80 \times 10^3 C

now we have

6.57 \times 10^{-2} = (6.80 \times 10^3)E

E = 9.66\times 10^{-6} N/C

direction is Horizontal

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A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal compon
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First of all, let's write the equation of motions on both horizontal (x) and vertical (y) axis. It's a uniform motion on the x-axis, with constant speed v_x=30 m/s, and an accelerated motion on the y-axis, with initial speed v_y=20 m/s and acceleration g=9.81 m/s^2:
S_x(t)=v_xt
S_y(t)=v_y t- \frac{1}{2} gt^2
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v_y t -  \frac{1}{2}gt^2=0
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t=0 is the time of the beginning of the motion,
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3 years ago
A merry-go-round rotates from rest with an angular acceleration of 1.04 rad/s2. How long does it take to rotate through (a) the
Andrei [34K]

Answer:

(a) 4.38 s.

(b) 1.817 s

Explanation:

(a)

Using

θ = ω₀t +1/2αt² ................ Equation 1

Where θ  = number of revolution, t = time, α = angular acceleration,  ω₀ = angular velocity.

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9.992 = 0(t) + 1/2(1.04)(t²)

t² = (2×9.992)/1.04

t² = 19.984/1.04

t = √(19.215)

t =4.38 s.

(b)

also using

θ = ω₀t +1/2αt²............... Equation 1

Given: θ  =3.18 rev = 3.18×2π = 19.97 rad,  ω₀ = 0 rad/s, α = 1.04 rad/s².

Substitute into equation 1

19.97 = 0(t) + 1/2(1.04)(t²)

t² = 19.97×2/1.04

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t = 6.197 s

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Answer:

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