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bekas [8.4K]
2 years ago
6

I NEED HELP ASAP I WILL MARK BRAINLEST.

Mathematics
1 answer:
lbvjy [14]2 years ago
3 0

Answer:

I believe it is the first option

2.7 x 10^-5

Step-by-step explanation:

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C. (5,7)

Step-by-step explanation:

One endpoint at 1,3 and the midpoint at 3,5Your answer would be to as two to each the x and y of the midpoint. So the answer would be 5,7.

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2

Step-by-step explanation:

So to figure this out we just need to flip the values of x and y in the table and then redefine that as the function g(x), because an inverse is essentially the reverse!

So if we flipped x and y's for f(x). We would see that our output or y of g(x) is -3 when x = 2, or in other words g(2) = -3. This means that we are now going to solve for when f(-3). So now lets look at the table and find the value at x = -3 for f(x). This value is 2, so the value of f(g(2)) = 2.

*In the future*

When you have a composite function of two inverses they essentially cancel out and would leave whatever the value of x is. So if we know f(x) and g(x) were inverses the value of f(g(2)) would just be 2.

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8 0
3 years ago
Read 2 more answers
Please can you answer this ASAP
Misha Larkins [42]

Answer:

x = 2

Step-by-step explanation:

\rm Solve \:  for \:  x: \\  \rm  \longrightarrow 4 (3 x - 1) = 20 \\  \\  \rm Divide  \: both  \: sides \:  of  \: 4 (3 x - 1) = 20  \: by  \: 4: \\  \rm  \longrightarrow  \dfrac{4(3x - 1)}{4}  =  \dfrac{20}{4}  \\  \\  \rm \dfrac{4}{4}  = 1: \\  \rm  \longrightarrow 3 x - 1 =  \dfrac{20}{4}  \\  \\  \rm \dfrac{20}{4} = 5: \\  \rm  \longrightarrow 3 x - 1 = 5 \\  \\  \rm Add \:  1  \: to  \: both  \: sides: \\  \rm  \longrightarrow 3 x + (1 - 1) = 1 + 5 \\  \\  \rm 1 - 1 = 0: \\  \rm  \longrightarrow 3 x = 5 + 1 \\  \\  \rm 5 + 1 = 6: \\  \rm  \longrightarrow 3 x = 6 \\  \\  \rm Divide \:  both  \: sides \:  of  \: 3 x = 6 \:  by \:  3: \\  \rm  \longrightarrow  \dfrac{3x}{3}  =  \dfrac{6}{3}  \\  \\  \rm \dfrac{3}{3}  = 1: \\  \rm  \longrightarrow x =  \dfrac{6}{3}  \\  \\  \rm \dfrac{6}{3}  = 2 : \\  \rm  \longrightarrow  x = 2

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