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vitfil [10]
1 year ago
4

A hypothetical metal has the bcc crystal structure, a density of 7.24 g/cm3, and an atomic weight of 48.9 g/mol. the atomic radi

us of this metal is:_______
Chemistry
1 answer:
Mandarinka [93]1 year ago
3 0

The atomic radius of this metal is 1.22 × 10⁻⁸ cm.

The atomic radius of a chemical element is a measure of the size of its atom.

d(metal) = 7.24 g/cm³; a density of a metal

M(metal) = 48.9 g/mol; an atomic weight of a metal

Na = 6.022×10²³; Avogadro's number

Z(metal) = 2;  number of atom the BCC unit cell

a = ?; the side length of the BCC unit cell

a = ∛Z×M /d×Na

a = ∛(2×48.9 g/mol) ÷ (7.24 g/cm³×6.022×10²³)

a = 2.82 × 10⁻⁸ cm

r = a×√3 / 4;  the atomic radius formula

r = 2.82 × 10⁻⁸ cm×√3 / 4

r = 1.22 × 10⁻⁸ cm

More about atomic radius: brainly.com/question/14831455

#SPJ4

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5 0
1 year ago
How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

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8 0
3 years ago
The volume of a gas sample is 22.4 liters at STP. The density of the gas is 1.34 grams per liter.
lozanna [386]

Answer:

The mass of gas is 30.02 g.

Explanation:

Given data:

Volume of gas = 22.4 L

Density of gas = 1.34 g/L

Mass of gas = ?

Solution:

The given problem will be solved through density formula.

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

Now we will put the values in formula.

1.34 g/L = m /22.4 L

m = 1.34 g/L × 22.4 L

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The mass of gas is 30.02 g.

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