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irga5000 [103]
1 year ago
8

1. We have new knowledge of how charge can be transferred from one object to another

Chemistry
1 answer:
NeX [460]1 year ago
5 0

Charge can be transferred from one object to another in three way conduction, polarization, and friction

Whenever electrons are transferred between objects, neutral matter becomes charged and three ways this can occur are referred to as conduction, polarization, and friction conduction means when there is direct contact between materials that differ in their ability to give up or accept electrons when two different materials are rubbed together, there is a transfer of electrons from one material to the other material and this causes one object to become positively charged (the electron loser) and the other object to become negatively charged (the electron gainer)

Here given object is water + balloon; balloon + wall; tape then you rub a balloon against your clothes and it sticks to the wall, you are adding a surplus of electrons (negative charges) to the surface of the balloon the wall is now more positively charged than the balloon and we tested the conductivity of deionized water positively charged

Know more about charge transferred one object to another

brainly.com/question/28661233

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Select all that apply:
Katyanochek1 [597]
OPTION B & C are the answers....
5 0
3 years ago
Which of the following represents the least number of molecues?
Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

Best of luck.

7 0
3 years ago
During translation, the new polypeptides are often directed to specific parts of the cell by the presence or absence of short se
kotegsom [21]

Answer:

The correct option is b. an amino-terminal signal

Explanation:

A polypeptide that will eventually fold to become an ion channel protein, it means a kind of integral membrane protein, has an amino terminal signal that indicates its delivery to endoplasmic reticulum (ER) and then to the membrane. This type of signal usually consist in a nucleus of 6 to 12 aminoacids and one or more basic aminoacids. Once the polypeptide enters the ER, this signal is removed.

6 0
3 years ago
I need help with chemistry :(
Yanka [14]

Answer:

How may we help kind sir

Explanation:

and if this was for points thanks

4 0
3 years ago
Read 2 more answers
Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9
galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = \frac{V_{2}}{3M_{1}V_{1}}=0.928M

3 0
3 years ago
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