Answer:
The thermal conductivity of the wall = 40W/m.C
h = 10 W/m^2.C
Explanation:
The heat conduction equation is given by:
d^2T/ dx^2 + egen/ K = 0
The thermal conductivity of the wall can be calculated using:
K = egen/ 2a = 800/2×10
K = 800/20 = 40W/m.C
Applying energy balance at the wall surface
"qL = "qconv
-K = (dT/dx)L = h (TL - Tinfinity)
The convention heat transfer coefficient will be:
h = -k × (-2aL)/ (TL - Tinfinty)
h = ( 2× 40 × 10 × 0.05) / (30-26)
h = 40/4 = 10W/m^2.C
From the given temperature distribution
t(x) = 10 (L^2-X^2) + 30 = 30°
T(L) = ( L^2- L^2) + 30 = 30°
dT/ dx = -2aL
d^2T/ dx^2 = - 2a
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Given,
A player kicks a soccer hits at an angle of 30° at a speed of 26 m/s
We can resolute the trajectory of soccer into horizontal and vertical components.(Please see the attached file)
We can have,
Horizontal velocity component of ball= 26cos(30°) = 26×(√3÷2) = 22.51 m/s
And vertical velocity component of ball = 26sin(26°) = 26×(1÷2) = 13 m/s
Answer: 7200 m
Explanation: The solution is, first convert 15 minutes to seconds.
15 mins x 60 s / 1 min = 900 s
Use the formula for speed which is v= d/t then derive for d.
d = vt
= 8 m/s ( 900s)
= 7200 m
Answer:
The burden distance is 7 ft
Solution:
As per the question:
Specific gravity of package emulsion, 
Specific gravity of diabase rock, 
Diameter of the packaged sticks, d = 3 in
Now,
To calculate the first trail shot burden distance, B:
![B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2SG_%7BE%7D%7D%7BSG_%7BR%7D%7D%20%2B%201.5%5D%5Ctimes%20d)
![B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2%5Ctimes%201.25%7D%7B2.76%7D%20%2B%201.5%5D%5Ctimes%203%20%3D%207.22)
B = 7 ft
