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kolezko [41]
3 years ago
7

HELP ASAP

Physics
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

1)a- mass never changes as you move from the earth

2)actually am not sure I haven't been taught that too

3)b

4)a-it doesn't depend only on mass but also weight

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Which of the following is most closely related to the specific heat of a substance?A. its temperatureB. its melting pointC. its
swat32

Answer:

option (C)

Explanation:

The amount of heat required to raise the temperature of substance of unit mass by unit degree is called specific heat of that substance.

Its SI unit is Joule / Kg °C.

Every material has a constant value of specific heat.

So, option (c) is correct.

4 0
3 years ago
As an object rolls downhill, some of the energy is
Charra [1.4K]
When the object is at the top of the hill it has the most potential energy. If it is sitting still, it has no kinetic energy. As the object begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the object at the top of the hill is getting converted into kinetic energy. Hope this helped. :)


7 0
3 years ago
Read 2 more answers
A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s
JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of  = 3.84 m/s

angle of the rain drop = 25°                      

tan θ = \dfrac{v}{u}                      

tan 25° = \dfrac{v}{3.84}                      

v =3.84 × tan 25°                      

v = 1.79 m/s                  

hence, the train is moving at the speed of v = 1.79 m/s

3 0
3 years ago
An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f
soldi70 [24.7K]

Answer:

D.

Explanation:

To solve the exercise it is necessary to apply the concepts related to the Magnetic Field described by Faraday.

The magnetic field is given by the equation:

B = \frac{\mu_0 I}{2\pi d}

Where,

\mu = Permeability constant

d = diameter

I = Current

For the given problem we have a change in the diameter, twice that of the initial experiment, therefore we define that:

B_1 = \frac{\mu_0 I}{2\pi d}

B_2 = \frac{\mu_0 I}{2\pi 2d}

The ratio of change between the two is given by:

\frac{B_2}{B_1} = \frac{\frac{\mu_0 I}{2\pi d}}{\frac{\mu_0 I}{2\pi 2d}}

\frac{B_2}{B_1} = \frac{d}{2d}

\frac{B_2}{B_1} = \frac{1}{2}

B_2 = B_1 \frac{1}{2}

Therefore the correct answer is D.

4 0
2 years ago
Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri
Lady bird [3.3K]

Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

\int dW = \int_0^{0.1} k.x dx

W = \int_0^{0.1} k.x dx

W = k[\dfrac{x^2}{2}]_0^{0.1}

10 = k\dfrac{0.1^2}{2}

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

W = \int_{0.1}^{0.2} 2000 x dx

W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

4 0
3 years ago
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