Answer:
0.54m
Explanation:
Step one:
given data
length of seesaw= 3m
mass of man m1= 85kg
weight = mg
W1= 85*10= 850N
mass of daughter m2= 35kg
W2= 35*10= 350N
distance from the center= (1.5-0.2)= 1.3m
Step two:
we know that the sum of clockwise moment equals the anticlockwise moment
let the distance the must sit to balance the system be x
taking moment about the center of the system
350*1.3=850*x
455=850x
divide both sides by 850
x=455/850
x=0.54
Hence the man must sit 0.54m from the right to balance the system
Okay, so lets look at the equation.
The Skate accelerates at 2.0m/s². This can confuse some people but basically all you need to do is plug in the seconds.
So lets do 1 second. It would be 2.0m/1² which is 2.0m.
Lets do 2 seconds. It would be 2.0m/2² which is 0.5m.
Lets do 3 seconds. It would be 2.0m/3² which is 0.222m
Lets do 3.5 seconds which is about 0.163m.
Add those together and you get 2.885m.
This may be wrong but this is what I got given what you gave (that its seconds squared).
a is the correct
Explanation:
hope you like then comment
The working equation for this problem is a derived equation from the rectilinear motion at constant acceleration. The equation is written below:
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
Of course, the plane starts from rest, so v₀ = 0. The final velocity is the liftoff speed which is v = 120 km/h. Substituting the values:
2a(270 m) = (120 km/h)² - 0²
Solving for a,
a = 26.67 km/h²
Answer:
17.46° W of N
Explanation:
His prow must point westward so that the westward component of his total velocity is equal to the eastward river speed.
3 = 10sinθ
sinθ = 3/10
θ = 17.4576... or about 17.46° W of N
it will take him 5 / 10cos17.46 = 0.52414... hrs. or about 31 min 27 s to cross.
