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mestny [16]
1 year ago
12

Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) CrO₄²⁻(aq) + Cu(s) → CrOH₃(s) + CuOH

₂(s)
Chemistry
1 answer:
andrew-mc [135]1 year ago
4 0

The balanced skeleton reactions are given below

2CrO₄²⁻(aq) + 3Cu(s)  +8H_{2} O(l) → 2Cr(OH)₃(s) + 3Cu(OH)₂(s) + 6OH^{-}(aq)

The oxidising agent and  reducing agents are Cr and  Cu .

There are following steps involve in balance redox reaction in basic medium .

  • First divide the reaction into two half reactions which give oxidation and reduction half reaction.
  • Then balance the elements other than oxygen and hydrogen atom.
  • Balance the oxygen atom by adding H_{2} O where number of oxygen is less .
  • Balance the hydrogen atom by adding H^{+} on another side of where water molecule added.
  • Add OH^{-} ions to both sides to neutralize  H^{+} ion.
  • Combine  H^{+} and OH^{-} ion to make H_{2} O .
  • Balance the charge by adding e^{-} .
  • Add the half reaction  .

The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction  is called reducing agent .

To learn more about reducing agents please click here ,

brainly.com/question/2890416

#SPJ4

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<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of carbon dioxide = 8.5\times 10^{-5}M

Volume of solution = 0.550 L

Putting values in above equation, we get:

8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 4.675\times 10^{-3} moles of carbon dioxide will contain = (6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21} number of molecules

Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

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3 years ago
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This is a double displacement or double replacement reaction. The reacting species exchange their partners. We can see here that both the sodium ion and chromium II ion both exchanged partners and picked up each others partners in the product.

Sodium ions and nitrate ions now remain in the solution while chromium II hydroxide which is insoluble is precipitated out of the solution as a solid hence the answer.

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