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mestny [16]
1 year ago
12

Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) CrO₄²⁻(aq) + Cu(s) → CrOH₃(s) + CuOH

₂(s)
Chemistry
1 answer:
andrew-mc [135]1 year ago
4 0

The balanced skeleton reactions are given below

2CrO₄²⁻(aq) + 3Cu(s)  +8H_{2} O(l) → 2Cr(OH)₃(s) + 3Cu(OH)₂(s) + 6OH^{-}(aq)

The oxidising agent and  reducing agents are Cr and  Cu .

There are following steps involve in balance redox reaction in basic medium .

  • First divide the reaction into two half reactions which give oxidation and reduction half reaction.
  • Then balance the elements other than oxygen and hydrogen atom.
  • Balance the oxygen atom by adding H_{2} O where number of oxygen is less .
  • Balance the hydrogen atom by adding H^{+} on another side of where water molecule added.
  • Add OH^{-} ions to both sides to neutralize  H^{+} ion.
  • Combine  H^{+} and OH^{-} ion to make H_{2} O .
  • Balance the charge by adding e^{-} .
  • Add the half reaction  .

The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction  is called reducing agent .

To learn more about reducing agents please click here ,

brainly.com/question/2890416

#SPJ4

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Answer:

32°F

Explanation:

Water freezes at 32°F.

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How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.
Westkost [7]

Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

5 0
3 years ago
A sample of lithium sulfate, (Li2SO4), has 2.94 x 1023 atoms
Crazy boy [7]

Answer:

0.245 moles

Explanation:

moles of lithium = 2*moles of Li2SO4

so moles of LI2SO4=2.94*10^23/(2*6*10^23)=0.245

3 0
2 years ago
The smell of hot food moves faster than the smell of cold food. Which property of gas is responsible for this?
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The answer would be kinetic energy. :)
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Fermium-253 is a radioactive isotope of fermium that has a half-life of 3.0 days. A scientist obtained a sample that contained 2
Dahasolnce [82]

Problem 2

You start out with 216 ugrams of Fermium - 253. After 3 days, you will have 1/2 as much. 108 ugrams is what you have.

Another 3 days goes by. You started with 108 ugrams. That gets cut in 1/2 again. Now you have 54 ugrams.

Finally another 3 days goes by. You started with 54 ugrams. you now have 1/2 as much which would be 27 ugrams

#days              Amount in micrograms

0                              216

3                               108

6                                54

9                                27

Problem One

You are using Nitrogen as your base example. The first thing you should do is fill in the table. Then you should try and make some rules. You need the rules in case the exam you are preparing for picks a different element to talk about these bond tendencies. In any event, it's handy to think this way.

<em><u>Table</u></em>

Bond               Energy Kj/Mol               Bond Length pico meters

N - N                 167                                                145

N=N                  418                                                125

N≡N                  942                                               110

<em><u>Rules</u></em>

As the number of bonds INCREASES, the energy contained in the bond goes UP

As the number of bonds INCREASES, the length of the bond goes DOWN.

5 0
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