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Anarel [89]
1 year ago
8

What is the percent yield of a reaction in which 61.7 g of tungsten(vi) oxide (wo3) reacts with excess hydrogen gas to produce m

etallic tungsten and 9.45 ml of water (d = 1.00 g/ml)? -chegg
Chemistry
1 answer:
Musya8 [376]1 year ago
5 0

The percent yield of a reaction in which 61.7 g of tungsten(vi) oxide (wo3) reacts with excess hydrogen gas is 15.31 grams.

<h3>What is the percent yield?</h3>

The percent yield is the yield that is calculated by dividing the actual yield by the theoretical yield multiplied by 100. This is the yield that is the difference between theoretical and actual yield.

Percent Yield ={Actual Yield} / {Theoretical Yield} x100 %

The actual yield is = 9.45 ml of water

Theoretical Yield =  61.7 g of tungsten

Percent yield = 9.45 / 61.7 g x 100 = 15.31 grams.

Thus, the percent yield of a reaction is 15.31 grams.

To learn more about percent yield, refer to the link:

brainly.com/question/17042787

#SPJ4

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