Answer:
Explanation:
just use avogardo's number which show that 1 mole has 6.022×10^23 atoms. so if you have 6.33 x 10^24 atoms of C, just divide that by 6.022x 10^23 and plug it into a calculator.
(6.33x10^24) / (6.022 x 10^23)
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N = 4 moles of Ar2, P = 1.90 atm, V = ?
T = 50C = 273 + 50K = 323K
PV = nRT --> V = nRT/P
V = (4)(.0821)(323)/1.90
V = 106.07/ 1.9
V = 55.8 L
Answer:
40 (superscript) is the mass number aka atomic mass, and 19 (subscript) is the atomic number aka number of protons and electrons.