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Which is the common ion when sodium sulfate is added to a solution of barium sulfate? na + ba 2+ so4 2 –?

aliya0001 [1]

The compound sodium sulfate is made of sodium ion and sulfate ion.

The formula can be written as Na₂SO₄.

The cation present in this compound is Na⁺ and the anion is SO₄²⁻.

The compound barium sulfate is made of barium ion and sulfate ion.

The formula can be written as BaSO₄.

This compound contains the cation Ba²⁺ and anion SO₄²⁻.

From the above , we can see that both the compounds have common anion which SO₄²⁻

So, the sulfate, SO₄²⁻ is the common ion when sodium sulfate is added to a solution of barium sulfate

6 0

3 years ago

Read 2 more answers

How many grams are in 3.67 moles of lithium cyanide

OLga [1]

Answer: 120.9 grams

Explanation:

Given the question : How many grams are in 3.67 moles of Lithium cyanide?

Chemical formula of lithium cyanide = LiCN

Molar mass of LiCN: Li = 6.941 ; C = 12, N = 14

LiCN = (6.941 + 12 + 14). = 32.941 g/mol

(Gram of substance / mole of substance) = (molar mass of substance / one mole)

(Gram of substance / 3.67) = (32.941 / 1)

= gram * 1 = 3.67 * 32.941

Gram of substance = 120.89347

= 120.9 grams

5 0

4 years ago

3 Cu + SHNO3 — 3 Cu(NO3)2 + 2 NO + 4 H20

LenaWriter [7]

Considering the reaction stoichiometry, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.

<h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

The molar mass of the compounds present in the reaction is:

Cu: 63.54 g/mole
HNO₃: 63 g/mole
Cu(NO₃)₂: 187.54 g/mole
NO: 30 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:

Cu: 3 moles ×63.54 g/mole= 190.62 grams

HNO₃: 8 moles ×63 g/mole= 504 grams

Cu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 grams

NO: 2 moles ×30 g/mole= 60 grams

H₂O: 4 moles ×18 g/mole= 72 grams

<h3>Mass of H₂O produced</h3>

It is possible to determine the the amount of mass of H₂O produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 72 grams of H₂O, if 11.9 moles of HNO₃ react how much mass of H₂O will be formed?

$mass of H_{2}O=\frac{11.9 moles of HNO_{3} x72 grams of H_{2}O}{8 moles of HNO_{3}}$