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klasskru [66]
2 years ago
9

Which particles contribute to the net charge and how does each change the net charge?

Physics
1 answer:
Licemer1 [7]2 years ago
3 0

The two subatomic particles that contribute to the net charge of an ion are electrons and protons.

<h3>What is an atom?</h3>

Atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.

The atom is made up of three components called subatomic particles as follows;

  • Protons
  • Electrons
  • Neutrons

The proton is the positively charged subatomic particle forming part of the nucleus of an atomwhile the electron is the subatomic particle having a negative charge and orbiting the nucleus.

This suggests that the two subatomic particles that contribute to the net charge of an ion are electrons and protons. That is;

Net charge = protons - electrons

Learn more about subatomic particles at:brainly.com/question/13303285

#SPJ1

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A 65.8-kg person throws a 0.0413 kg snowball forward with a ground speed of 32.5 m/s. A second person, with a mass of 58.7 kg, c
guapka [62]

Answer:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

Explanation:

The statement is described physically by means of the Principle of Momentum Conservation. Let assume that first person moves in the positive direction:

First Person

(65.8\,kg)\cdot (2.51\,\frac{m}{s}) = (65.8\,kg)\cdot v_{1} + (0.0413\,kg)\cdot (32.5\,\frac{m}{s} )

Second Person

(0.0413\,kg)\cdot (32.5\,\frac{m}{s})+(58.7\,kg)\cdot (0\,\frac{m}{s})=(0.0413\,kg+58.7\,kg)\cdot v_{2}

The final velocities of the two people after the snowball is exchanged is:

v_{1} = 2.490\,\frac{m}{s}

v_{2} = 0.023\,\frac{m}{s}

6 0
3 years ago
How much physical activity should an adult have each week?
Mars2501 [29]

d 30 minutes a day , 5 days a week

4 0
3 years ago
Read 2 more answers
How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, assume
Svetach [21]

Answer:

9.56\cdot 10^{-7} C

Explanation:

A parallel-plate capacitors consist of two parallel plates charged with opposite charge.

Since the distance between the plates (1 cm) is very small compared to the side of the plates (19 cm), we can consider these two plates as two infinite sheets of charge.

The electric field between two infinite sheets with opposite charge is:

E=\frac{\sigma}{\epsilon_0}

where

\sigma=\frac{Q}{A} is the surface charge density, where

Q is the charge on the plate

A is the area of the plate

\epsilon_0 = 8.85\cdot 10^{-12}F/m is the vacuum permittivity

In this problem:

- The side of one plate is

L = 19 cm = 0.19 m

So the area is

A=L^2=(0.19)^2=0.036m^2

Here we want to find the maximum charge that can be stored on the plates such that the value of the electric field does not overcome:

E=3\cdot 10^6 N/C

Substituting this value into the previous formula and re-arranging it for Q, we find the charge:

E=\frac{Q}{A\epsilon_0}\\Q=EA\epsilon_0 = (3\cdot 10^6)(0.036)(8.85\cdot 10^{-12})=9.56\cdot 10^{-7} C

7 0
3 years ago
An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?
xz_007 [3.2K]

Answer:

26.5 m

Explanation:

x_{o} = initial position of the object = 75.2 m

x  = final position of the object

d  = displacement of the object = - 48.7  

Displacement of the object is given as the difference of final and initial position of the object

d = x - x_{o}

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

8 0
3 years ago
How do I find the velocity of a moving object?
Aliun [14]
If you know the distance and the time I travelled that distance.


You just have to divide the time from the distance to get velocity

V =d
_

t
8 0
3 years ago
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