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2 years ago

What are becquerel rays????

Physics

2 answers:

Olenka [21]2 years ago

7 0

Becquerel works with uranium and its compounds, they consist of a mixture of alpha, beta, and gamma rays

Nonamiya [84]2 years ago

5 0

Becqerel rays are quickly established that a variety of uranium salts, whether phosphorescent or not, have the same property; proving that the radiation is an intrinsic characteristic of uranium. He referred to the emitted rays as 'uranic rays', and was able to show that they could electrify the air.

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Starting from rest, a 5.00-kg block slides 2.50 m down a rough 30.0 incline. The coeffi cient of kinetic friction between the bl

UkoKoshka [18]

Answer:

a) $W_g =61.25J$

b) $W_k = -46.25J$

c) $W_N = 0$

d) $W_g$ would be the same.

$W_k$ would decrease.

$W_N$ would be the same.

Explanation:

a) On an inclined plane the force of gravity is the sine component of the weight of the block.

$F_g = mg\sin(\theta) = 5(9.8)\sin(30^\circ)\\W_g = F_g x = 5(9.8)\sin(30^\circ)2.5 = 61.25J$

b) The friction force is equal to the normal force times coefficient of friction.

$F_k = -mg\cos(\theta)\mu_k = -5(9.8)cos(30^\circ)0.436 = -18.5 N\\W_k = -F_kx = -46.25J$

c) The work done by the normal force is zero, since there is no motion in the direction of the normal force.

d) The relation between the vertical height and the distance on the ramp is

$h = x\sin(\theta)$

According to this relation, the work done by the gravity wouldn't change, since the force of gravity includes a term of $x\sin(\theta)$ .

The work done by the friction force would decrease, because both the cosine term and the distance on the ramp would decline.

The work done by the normal force would still be zero.

5 0

2 years ago

An average human weighs about 600 N

NemiM [27]

Answer:

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

<em> $F=\frac{1}{4\pi\epsilon_{0}}\frac{qq}{x^{2}}$ </em>

Where,

$\frac{1}{4\pi\epsilon_{0}}$ = 9 x 10⁹ N m² C⁻²

Therefore

x² = 9 x 10⁹ X 1.5² / 600

= 33750000

x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

4 0

2 years ago

Who was the last person to step on the moon?

Pavlova-9 [17]

Eugene Cernan was not the last, but he was the most recent.

5 0

2 years ago

Read 2 more answers

Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist

steposvetlana [31]

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge $q = -6.25 \times 10^{-6}$ C

Separation between two charges $r = 0.02$ m

For finding the electrical force,

According to the coulomb's law

$F = \frac{k q^{2} }{r^{2} }$

Here, force between two balloons are repulsive because both charges are same.

Where $k = 9 \times 10^{9}$

$F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2} }{4 \times 10^{-4} }$

$F = 878.9$ N

Therefore, the electric force between them is 878.9 N

8 0

2 years ago

Three blocks are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box o

Lina20 [59]

Answer:

A) M

Explanation:

The three blocks are set in series on a horizontal frictionless surface, whose mutual contact accelerates all system to the same value due to internal forces as response to external force exerted on the box of mass M (Newton's Third Law). Let be F the external force, and F' and F'' the internal forces between boxes of masses M and 2M, as well as between boxes of masses 2M and 3M. The equations of equilibrium of each box are described below:

Box with mass M

$\Sigma F = F - F' = M\cdot a$