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Andrew [12]
3 years ago
6

What are becquerel rays????

Physics
2 answers:
Olenka [21]3 years ago
7 0
Becquerel works with uranium and its compounds, they consist of a mixture of alpha, beta, and gamma rays
Nonamiya [84]3 years ago
5 0

Becqerel rays are quickly established that a variety of uranium salts, whether phosphorescent or not, have the same property; proving that the radiation is an intrinsic characteristic of uranium. He referred to the emitted rays as 'uranic rays', and was able to show that they could electrify the air.

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The sun is 1.5 × 108 km from Earth. The index of refraction for water is 1.349. How much longer would it take light from the sun
tankabanditka [31]

Answer:

175s

Explanation:

time it takes sunlight to reach the earth in  vacuum

C=light speed=299792458m/s

X=1.5x10^8km=1.5x10^11m

c=X/t

T1=X/c

T1=1.5X10^11/299792458=500.34s

time it takes sunlight to reach the earth in  water:

First we calculate the speed of light in water taking into account the refractive index

Cw=299792458m/s/1.349=222233104.5m/s

T2=1.5x10^11/222233104.5m/s=675s

additional time it would take for the light to reach the earth

ΔT=T2-T1=675-500=175s

4 0
3 years ago
16 to 19 year old male and females are how much more likely to be involved in a crash?
Sedbober [7]
I say around 40% - 60%

https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp

(I just corrected the question. Sorry if it is still incorrect.)
6 0
3 years ago
The additional product of the nuclear fission reaction shown in the
Arada [10]
The answer to your question is C.
8 0
3 years ago
HELP PLEASE
Ira Lisetskai [31]
The answer is magnet away from the coil
3 0
3 years ago
Read 2 more answers
Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s and a speed of 42.0 m/s.
ss7ja [257]

Answer:

Force, |F| = 2100 N

Explanation:

It is given that,

Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s, \dfrac{m}{t}=50\ kg/s

Initial speed, v = 42 m/s

The momentum is reduced to zero, final speed, v = 0

The relation between the force and the momentum is given by :

F=\dfrac{p}{t}

F=\dfrac{mv}{t}

F=50\ kg/s\times 42\ m/s

|F| = 2100 N

So, the magnitude of the force exerted on the wall is 2100 N. Hence, this is the required solution.

8 0
3 years ago
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