Answer:
The pH of the 0.100 M solution of hydobromous acid HBrO is 4.843
Explanation:
Here we have the reaction given as follows;
HBrO ⇄ H⁺ + BrO⁻¹
Therefore;
HBrO ⇄ H⁺ + BrO⁻¹
Initial concentration of HBrO = 0.100 M decomposes partly to form x moles of each of H⁺ and BrO⁻¹. That is
HBrO ⇄ H⁺ + BrO⁻¹
Initial 0.1 0 0
Change -x +x +x
Equilibrium 0.1 - x x x
Hence;
![Ka = \frac{[H^+][BrO^{-1}]}{[HBrO]} =\frac{x \times x }{0.1 - x} = \frac{x^2}{0.1 -x} = 2.06 \times 10^{-9}](https://tex.z-dn.net/?f=Ka%20%3D%20%20%5Cfrac%7B%5BH%5E%2B%5D%5BBrO%5E%7B-1%7D%5D%7D%7B%5BHBrO%5D%7D%20%3D%5Cfrac%7Bx%20%5Ctimes%20x%20%7D%7B0.1%20-%20x%7D%20%3D%20%5Cfrac%7Bx%5E2%7D%7B0.1%20-x%7D%20%3D%202.06%20%5Ctimes%2010%5E%7B-9%7D)
(0.1 - x) × 2.06×10⁻⁹ = x²
x² + 2.06×10⁻⁹·x - 0.1 = 0
Factorizing gives;
(x + 1.4354×10⁻⁵)(x - 1.4352×10⁻⁵) = 0
Therefore, x = 1.4352×10⁻⁵ M or -1.4354×10⁻⁵ M
We take the positive value as x is the concentration of the ions in the solution;
From the above [H⁺] = 1.4352×10⁻⁵ M
pH = -log[H⁺] = -log(1.4352×10⁻⁵) = 4.843
The pH of the 0.100 M solution of hydobromous acid HBrO at 298 K where the Ka = 2.06×10⁻⁹ = 4.843.
Answer:
The particles of fluids are constantly moving in all directions at random. As the particles move, they keep bumping into each other and into anything else in their path. These collisions cause pressure, and the pressure is exerted equally in all directions.
Answer:
[H⁺] = 5.754 x 10^-13 M
Explanation:
Since pH is the negative log of the hydronium concentration, we can solve for hydronium concentration and then plug in our given pH:
pH = -log[H⁺]
-pH = log[H⁺]
10^-pH = [H⁺]
Let's plug in our pH:
[H⁺] = 10^-pH = 10^-12.24 = 5.754 x 10^-13 M
CuSO₄+ Zn = Cu + ZnSO₄
1 mole Zn ---------> 1 mole Cu
3.8 mole Zn ------> ?
moles Cu = 3.8 x 1 / 1
= 3.8 moles of Cu
hope this helps!
Answer:
On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.
Explanation:
