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daser333 [38]
3 years ago
15

What is the formula used to calculate the heat required to warm or cool one phase of matter

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

SPECIFIC HEAT CAPACITY

Explanation:

Q = MC DELTA T

q = heat

c = specific heat

T = temperature ( final - initial )

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Organic compounds and their uses​
Leviafan [203]
Organic compounds essential to human functioning include carbohydrates, lipids, proteins, and nucleotides. These compounds are said to be organic because they contain both carbon and hydrogen
7 0
2 years ago
If a 66.5 g sample of ammonium nitrate (NH4NO3) is dissolved in enough water to make 315 mL of solution, what will be the molari
11111nata11111 [884]

Answer:

2.64 M

Explanation:

To find the molarity, you need to (1) convert grams to moles (via molar mass), then (2) convert mL to L, and then (3) calculate the molarity (via molarity ratio). The final answer should have 3 sig figs to match the sigs figs of the given values.

(Step 1)

Molar Mass (NH₄NO₃): 2(14.007 g/mol) + 4(1.008 g/mol) + 3(15.998 g/mol)

Molar Mass (NH₄NO₃): 80.04 g/mol

66.5 grams NH₄NO₃                1 mole
---------------------------------  x  ----------------------  =  0.831 moles NH₄NO₃
                                             80.04 grams

(Step 2)

1,000 mL = 1 L

 315 mL                1 L
--------------  x  ------------------  =  0.315 L
                        1,000 mL

(Step 3)

Molarity = moles / volume

Molarity = 0.831 moles / 0.315 L

Molarity = 2.64 M

7 0
2 years ago
21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
-You wish to make a 0.203 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated
lubasha [3.4K]

For all three questions, we will use the fact that

  • molarity = (moles of solute)/(liters of solution)

1) For 175 mL of solution at 0.203 M, this means that:

  • 0.203 = (moles of solute)/0.175
  • moles of solute = 0.035523 mol

Considering the hydrochloric acid solution, if we have 0.035523 mol, then:

  • 6.00 = 0.035523/(liters of solution)
  • liters of solution = 0.035523/6.00 = 0.0059205 = <u>5.92 mL (to 3 sf)</u>

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2) If there is 20.3 mL = 0.0203 L, then:

  • 8.20 = (moles of solute)/0.0203
  • moles of solute = 0.16646 mol

This means that the molarity of the diluted solution is:

  • 0.16646/(0.200) = <u>0.832 M (to 3 sf)</u>

<u />

3) If we need 1.50 L of 0.700 M solution, then:

  • 0.700 = (moles of solute)/1.50
  • moles of solute = 1.05 mol

Considering the 9.36 M acid solution, from which we need 1.05 mol of perchloric acid from,

  • 9.36 = 1.05/(liters of solution)
  • liters of solution = 1.05/9.36, which is 0.11217948717949 L, or <u>112 mL (to 3 sf)</u>
8 0
2 years ago
Why can filtration not be used to seperate a mixture of 2 liquids ​
Salsk061 [2.6K]

Answer:

Filtration works best when the solute isn't dissolve in the solvent. For instance, sand and water can be seperated through filtration because both compounds do not dissolve with each other. However, sugar and water would not be seperated through filtration as they dissolve with each other.

-google :)

3 0
3 years ago
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