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DiKsa [7]
1 year ago
7

Write the physics equation for this graph in slope-intercept form (y=mx+b), expressed in terms of the appropriate variables.

Physics
1 answer:
alexgriva [62]1 year ago
4 0

The equation that describes the graph is y = 16.7x + 150.

<h3>What is the equation?</h3>

We have been given the graph of a certain function data set in physics. We know that the graph is the representation of data on cartesian coordinates. In this case, we are asked to find the equation of the graph in the form; y=mx+b

m = slope of the graph

b = intercept of the graph.

To obtain the slope;

m = y2 - y1/ x2 - x1

m = 400 - 200/ 16 - 4

m = 200/ 12

m = 16.7

Then we can see from the graph that the y - intercept is 150. Having these data, the equation that could describe the graph is now;

y = 16.7x + 150

Learn more about graph:brainly.com/question/13301664

#SPJ1

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r = distance between Sun and Moon = distance between Sun and Earth - distance between Earth and Moon = 149,600,000 km - 384,400 km

<span>g = 0.00596 m/s^2</span>
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A space craft is traveling in interplanetary space at a constant velocity. what is the estimated distance traveled by the space
mina [271]

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A. 2.30 x 10^2 kil

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Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app
Aleks04 [339]

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

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4 years ago
What is the resultant fore acting on a 500g object accelerating 5m/s2
zimovet [89]

2.5N

Explanation:

Given parameters:

Mass of object = 500g

Acceleration = 5m/s²

unknown:

Resultant force = ?

Solution:

According to Newton's second law "the net force on a body or the resultant force is the product of its mass and acceleration".

Resultant or net force = m x  a

where  m is the mass

         a is the acceleration

Now we need to convert the mass to kg

 1000g  = 1kg

 500g  = \frac{500}{1000} = 0.5kg

Therefore;

 Input the parameters:

    Force = 0.5 x 5 = 2.5N

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