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3 years ago

13

How many times heavier is a neutron than an electron?

1 answer:

PtichkaEL [24]3 years ago

4 0

An estimated difference in mass would be 1840

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Air flows through a nozzle at a steady rate. At the inlet the density is 2.21 kg/m3 and the velocity is 20 m/s. At the exit, the

Vitek1552 [10]

To solve the problem, it is necessary to apply the concepts related to the change of mass flow for both entry and exit.

The general formula is defined by

$\dot{m}=\rho A V$

Where,

$\dot{m} =$ mass flow rate

$\rho =$ Density

V = Velocity

Our values are divided by inlet(1) and outlet(2) by

$\rho_1 = 2.21kg/m^3$

$V_1 = 20m/s$

$A_1 = 60*10^{-4}m^2$

$\rho_2 = 0.762kg/m^3$

$V_2 = 160m/s$

PART A) Applying the flow equation we have to

$\dot{m} = \rho_1 A_1 V_1$

$\dot{m} = (2.21)(60*10^{-4})(20)$

$\dot{m} = 0.2652kg/s$

PART B) For the exit area we need to arrange the equation in function of Area, that is

$A_2 = \frac{\dot{m}}{\rho_2 V_2}$

$A_2 = \frac{0.2652}{(0.762)(160)}$

$A_2 = 2.175*10^{-3}m^2$

Therefore the Area at the end is $21.75cm^2$

3 0

3 years ago

The term _______ is used to indicate the frequency level of a sound.

aksik [14]

The answer is D, pitch

6 0

3 years ago

Read 2 more answers

A top of rotational inertia 4.0 kg m2 receives a torque of 2.4 nm from a physics professor. the angular acceleration of the body

Tanzania [10]

Angular acceleration is simply the ratio of the Torque over the rotation inertia, that is:

Angular acceleration = Torque / Rotational inertia

So substituting the values:

Angular acceleration = 2.4 N m / 4.0 kg m2

<span>Angular acceleration = 0.7 rad/s^2</span>

5 0

3 years ago

I need help with c-j !!

Tresset [83]

Answer:44

Explanation:

just add

8 0

3 years ago

A box slides down a 31° ramp with an acceleration of 0.99 m/s2. Determine the coefficient of kinetic friction between the box an

tino4ka555 [31]

Answer: $\mu$ =0.48

Explanation:

Given

inclination $\theta =31^{\circ}$

Acceleration of object $=0.99 m/s^2$

Now using FBD

$mg\sin \theta -f_r=ma$

$mg\sin \theta -\mu mg\cos \theta =ma$

$a=g\sin \theta -\mu g\cos \theta$

$0.99=5.04-\mu 8.4$

$\mu 8.4=4.057$

$\mu =0.48$

7 0

3 years ago