Answer:
6.1 × 10^9 Nm-1
Explanation:
The electric field is given by
E= Kq/d^2
Where;
K= Coulombs constant = 9.0 × 10^9 C
q = magnitude of charge = 1.62×10−6 C
d = distance of separation = 1.53 mm = 1.55 × 10^-3 m
E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2
E= 14.58 × 10^3/2.4 × 10^-6
E= 6.1 × 10^9 Nm-1
Answer:
ieces A and B must also have the same type of charges
Explanation:
In electrostatics, charges of the same sign repel and charges of different signs attract.
If we apply this to our case, we have that part A and C repel each other, therefore they have the same type of charge.
Also part A and C repel each other, therefore they have the same type of charge.
If we use the transitive property of mathematics, pieces A and B must also have the same type of charges
Solution:
The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :
Differentiating on both the sides with respect to time, we get
Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :
V/m-s
For displacement apply Pythagorean theorem
Answer:500hz
Explanation:
Frequency=velocity/wavelength
Frequency=1500/3
Frequency=500hz
