Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
Where:
I is the current (2 A)
Δt is the time (20 s)
Then, we can put this value of charge in the voltage equation.
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!
linear charge density of system of two line charges is given as
now as we know that electric field due to a line charge at some distance from it is given by
so here we will first find the electric field of first line charge at the position of other line charge
now as we know that
here q = charge on the line charge system at which force is required
E = electric field on that system of charge where force is required
now we can find the charge by
Now using the above formula
so force on the part of wire is F = 0.0811 N
The illumination of the book is found to be approximately equal to 15 lx.
Option 1.
Explanation:
Luminous flux is the measure of power of the light emitted from a source and illumination is the property of the light to illuminate a given surface when it falls on the surface. So the measure of the region the light flux illuminates the surface is termed as illumination.
As here the luminous flux is given as 1759 lm and the distance of the object which has to be illuminated is placed 3 m away from the source ,the illumination is found to be directly proportional to the luminous flux and inversely proportional to the square of the distance between them
So, the illumination of the book is found to be approximately equal to 15 lx.