Does this marble have potential energy?<br> 1) no<br> 2)yes

Which two factors decrease as the kinetic energy of the particles in an object decrease

Ostrovityanka [42]

The particle temperature and the valency of the atom in the particles are the two parameters that decrease with the kinetic energy of the particles in an item.

<h3>What is temperature?</h3>

Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

Because an item possesses kinetic energy when it is moving, anything that prevents that motion will reduce the kinetic energy of the object.

A valence electron is an electron in the outermost shell associated with an atom that can experience the innovation of a chemical bond if the outer shell is not closed. Both atoms contribute one valence electron to create a shared pair.

More the valence electron more the motion of atoms results in more kinetic energy,

Hence the two factors decrease as the kinetic energy of the particles in an object will be the particle temperature and the valency of the atom in the particles.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ2

3 0

1 year ago

A playground is on the flat roof of a city school, 6.2m above the street below. The vertical wall of the building is h=7.30m hig

olya-2409 [2.1K]

Answer:

a. 18.13m/s

b. 0.84m

c. 2.4m

Explanation:

a. to find the speed at which the ball was lunched, we use the horizontal component.Since the point distance from the base of the ball is 24m and it takes 2.20 secs to reach the wall,we can say that

t=distance /speed

$speed v_{x}=vcos\alpha=24/2.2=10.9m/s\\V=10.9/cos53^{0}\\V=18.13m/s$

Hence the speed at which ball was lunched is 18.13m/s

b. from the equation

$y=v_{y}t-\frac{1}{2}gt^{2}\\ v_{y}=18.13sin53=14.48m/s\\\\y=(14.48*2.2)-\frac{1}{2}9.8*2.2^{2}\\y=8.14m\\$

the vertical distance at which the ball clears the wall is

y=8.14-7.3=0.84m

c. the time it takes the ball to reach the 6.2m vertically

$6.2=14.47t-4.8t^{2}\\\\14.47t-4.8t^{2}-6.2=0\\\using\\t=-b±\frac{\sqrt{b^{2}-4ac} }{2a}\\ where \\a=-4.8, b=14.47t, c=6.2\\hence t=2.4secs$

the horizontal distance covered at this speed is

$y+24=(18.13cos53)2.4\\y=26.186-24\\y=2.12m$

4 0

3 years ago

Scientific models have two basic types. Please select the best answer from the choices provided T F

zubka84 [21]

Answer:

Scientific models have two basic types. FALSE.

Hoped I helped

3 0

3 years ago

Which of the following is an example of pure research? Creating new elements to study their properties Producing plastics that a

koban [17]

Creating new elements in order to study their properties is definitely pure research.
It has no earthly [known] application, since the elements don't even exist, whereas
for each of the other choices, you've stated the desired application as the reason
for the search.

6 0

2 years ago

When the k. E of

Ierofanga [76]

$\sqrt{2}$ Answer: