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Naya [18.7K]
2 years ago
10

Dr Spock would have supported which of the following actions by parents

Physics
1 answer:
Viefleur [7K]2 years ago
5 0
C. <span>A parent develops a set of rules collaboratively with her child.</span>
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Answer:

You take the light from a star, planet or galaxy and pass it through a spectroscope, which is a bit like a prism letting you split the light into its component colours. "It lets you see the chemicals being absorbed or emitted by the light source. From this you can work out all sorts of things," says Watson

8 0
2 years ago
Describe how charge is transferred from the ruler to the metal rod.
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When the ruler is broughı near the inetal knob, it repels electrons in the metal. Electrons move away froni the ruler and down the metal rod. The knob now has a positive charge. The thin pieces of metal foil at the bottom of the metal rod now have a negative charge.
3 0
3 years ago
Read 2 more answers
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
3 years ago
The mass of a truck with its cargo is 1800 kg. The truck is coasting to the right with a speed of 10 m/s. As it coasts its cargo
OverLord2011 [107]

Here we apply conservation of linear momentum. The momentum of the truck with cargo and without cargo remains constant. That is,

mv=m'v'.

Here m,v are initial mass and velocity. m',v' are final mass and velocity. Here m=1800,v=10 and m'=1800-300=1500.

The velocity of the truck be after its cargo is taken off is

v'=\frac{mv}{m'} \\  v'=\frac{1800*10}{1500} \\  v'=12 m/s

6 0
3 years ago
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Can a body having larger mass be hotter than another of smaller mass.expalain​
Rom4ik [11]

Answer:

it would make sense because a larger body could produce more body heat.

8 0
2 years ago
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