The number of solutions in each equation are as follows:
- 1 solution: 4^x = 2^{-x}
- 2 solution: 3/2x + 2 = 2^{x} + 1 and 3x + 1 = 2^{-x}.
- No solution: 4^x + 2 = 3^x - 1 and 2x - 5 = 3^{x} + 2.
<h3>How to determine the
number of solutions?</h3>
In order to determine the number of solutions, we would split the single equation to two different equations and then plot a graph, so as to reveal their solutions.
This ultimately implies that, the number of solutions is equal to the point of intersection between the lines of the equations plotted on a graph.
In conclusion, the number of solutions in each equation are as follows:
- 1 solution: 4^x = 2^{-x}
- 2 solution: 3/2x + 2 = 2^{x} + 1 and 3x + 1 = 2^{-x}.
- No solution: 4^x + 2 = 3^x - 1 and 2x - 5 = 3^{x} + 2.
Read more on number of solutions here: brainly.com/question/12558210
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Answer:
0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.
Step-by-step explanation:
Rain on November 1:
0.9 of 0.6(rain on Oct 31).
0.3 of 0.4(not rain on Oct 31).
Rain on November 2:
Considering rain on November 1, 0.9 probability of rain.
Rain on November 3:
Considering rain on November 2, 0.1 probability of rain.
Find the probability of rain on November 1 and 2, but not on November 3.
Multiplicating the probabilities:

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.
Answer: Third one.
Step-by-step explanation: