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2 years ago

The wavelength of a certain portion of an electromagnetic wave is 314 nm. what is its frequency and classification?

Physics

1 answer:

nadezda [96]2 years ago

5 0

The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.

<h3>What is meant by electromagnetic waves?</h3>

Electromagnetic waves are forms of energy that are invisible and travel throughout the universe. However, some of the effects of this energy are visible. The light that we see is a component of the electromagnetic spectrum.

Electromagnetic waves, or EM waves, are produced by vibrations between an electric field and a magnetic field. In other words, electromagnetic waves are made up of oscillating magnetic and electric fields.

<h3>How do you calculate the speed of an electromagnetic wave?</h3>

The wavelength and frequency of any periodic wave are used to calculate its speed. v = λf.

In free space, the speed of any electromagnetic wave is equal to the speed of light, c = 3 $*$ 108 m/s.

The frequency of the electromagnetic wave is 9.55 × 1014 Hz and it is classified as ultraviolet.

To learn more about electromagnetic wave refer to:

brainly.com/question/25847009

#SPJ4

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4 years ago

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3 years ago

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3 years ago

An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elect

beks73 [17]

Answer:

Speed of the alpha particle is $v=1.8180\times 10^3m/sec$

Explanation:

We have given charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of the alpha particle $m=6.68\times 10^{-27}kg$

Potential difference $V=-3.45\times 10^{-3}volt$

We have to find the speed of the alpha particle

From energy conservation we know that

$\frac{1}{2}mv^2=qV$

$\frac{1}{2}\times 6.68\times 10^{-27}\times v^2=3.2\times 10^{-19}\times 3.45\times 10^{-3}$

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3 years ago

An electron in an unknown energy level of a hydrogen atom transitions to the n=2 level and emits a photon with wavelength 410 nm

lyudmila [28]

Answer:

The initial energy level = 6

Explanation:

Photon wavelength is proportional to energy. The wavelength of emitted photons is related to the energy levels of the atom as given by the Rydberg formula:

ₕ₁₂

(1/λ) = Rₕ [(1/n₂²) − (1/n₁²)]

where n₂ = final energy level = 2

n₁ = initial energy level = ?

Rₕ = Rydberg's constant = 1.097 × 10⁷ m⁻¹

λ = wavelength = 410 nm = 410 × 10⁻⁹ m

1/(410 × 10⁻⁹) = (1.097 × 10⁷) [(1/2²) − (1/n₁²)]

0.223 = [(1/4) − (1/n₁²)]

(1/n₁²) = 0.02778

n₁² = 1/0.02778 = 36

n₁ = 6.

7 0

4 years ago