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3 years ago

Determine the specific heat of iron if 6.1 j of energy are needed to warm 1.50 g of iron from 20.0◦c to 29.0◦c?

1 answer:

8 0

As the iron core isprogressively laid down, the mechanism of iron oxidation changes from a protein dominated process with H202 being the primary product of O2 reduction to a mineral surface dominated process where H20 is the primary product. These results emphasize the importance of the apoferritin shell in facilitating iron oxidation in the early stage of iron deposition prior to significant development of the polynuclear iron core.

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When you catch a baseball with a glove (instead of your hand), the glove helps by

AveGali [126]

Answer:D. Impulse

Explanation:

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2 years ago

If the amount of gas in a sealed container increases, what happens to the pressure in the container

lilavasa [31]

The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. This can be easily understood by visualising the particles of gas in the container moving with a greater energy when the temperature is increased.

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2 years ago

Read 2 more answers

In the double-slit experiment with electrons, the electrons arrive at the screen in a

Y_Kistochka [10]

Answer:

B. Wave-like way with a pattern that is wave-like

Explanation:

The double slit experiment when performed with electromagnetic waves, gives a pattern of light lines and dark areas, equally spaced.

In the case of electrons we must use Broglie's duality principle that states that all things have the characteristics of particles and waves together. The characteristic observed in a given experiment depends on the type of experiment, using the relationship

p = h /λ

Where p is the amount of motion of the particle and λ the wavelength associated with this particle

In consequence of the previous one to the screen it should arrive as a wave with a wave type pattern

Let's review the answer.

A) False. The pattern is wave type

B) True. The whole process is with undulating characteristics

C) False. A wave arrives

D) False. A wave arrives

4 0

3 years ago

A sled of mass 50 kg is pulled along a snow-covered, flat ground. The static friction coefficient is 0.3 and the kinetic frictio

Diano4ka-milaya [45]

Answer:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled.

b) The weight of the sled is 490.35 newtons.

c) A force of 147.105 newtons is needed to start the sled moving.

d) A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

Explanation:

a) We kindly invite you to see below the Free Body Diagram of the forces acting on the sled. All forces are listed:

$F$ - External force exerted on the sled, measured in newtons.

$f$ - Friction force, measured in newtons.

$N$ - Normal force from the ground on the mass, measured in newtons.

$W$ - Weight, measured in newtons.

b) The weight of the sled is determined by the following formula:

$W = m\cdot g$ (1)

Where:

$m$ - Mass, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 50\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the weight of the sled is:

$W = (50\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$W = 490.35\,N$

The weight of the sled is 490.35 newtons.

c) The minimum force needed to start the sled moving on the horizontal ground is:

$F_{min,s} = \mu_{s}\cdot W$ (2)

Where:

$\mu_{s}$ - Static coefficient of friction, dimensionless.

$W$ - Weight of the sled, measured in newtons.

If we know that $\mu_{s} = 0.3$ and $W = 490.35\,N$ , then the force needed to start the sled moving is:

$F_{min,s} = 0.3\cdot (490.35\,N)$

$F_{min,s} = 147.105\,N$

A force of 147.105 newtons is needed to start the sled moving.

d) The minimum force needed to keep the sled moving at constant velocity is:

$F_{min,k} = \mu_{k}\cdot W$ (3)

Where $\mu_{k}$ is the kinetic coefficient of friction, dimensionless.

If we know that $\mu_{k} = 0.1$ and $W = 490.35\,N$ , then the force needed to keep the sled moving at a constant velocity is:

$F_{min,k} = 0.1\cdot (490.35\,N)$

$F_{min,k} = 49.035\,N$

A force of 49.035 newtons is needed to keep the sled moving at a constant velocity.

8 0

2 years ago

Why do waves in a tank are 10 cm long if they pass a point at a rate of 3.75 waves per second what is the speed in m/s?

AURORKA [14]

Answer: 0.0267m/s

Explanation: Wave speed in m/s

Speed = Distance/Time

Substitute the given values into the formula

Speed = 0.1/3.75

Speed = 0.0267m/s

7 0

2 years ago