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2 years ago

What is the SI unit for momentum? kg•m kg•m/s kg•m²/s Kg•m/s^2

Physics

1 answer:

stepan [7]2 years ago

4 0

Answer:Kg•m/s

Explanation:the SI unit for momentum is kg•m/s

Momentum=mass x velocity

Unit for mass=kg

Unit for velocity=m/s

Therefore they unit for momentum is kg•m/s

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The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which can

Sonja [21]

Answer:

Explanation:

a ) speed of passenger = circumference / time

= 2π R / Time

= 2 x 3.14 x 50 / 60

= 5.23 m /s

b )

centrifugal force = m v² /R

= (882 /9.8 ) x 5.23² / 50

= 77.47 N

Apparent weight at the highest point

real weight - centrifugal force

= 882 - 77.47

= 804.53 N

Apparent weight at the lowest point

real weight + centrifugal force

= 882 +77.47

= 959.47 N

c ) if the passenger’s apparent weight at the highest point were zero

centrifugal force = weight

mv² /R = mg

v² = gR

= 9.8 X 50

v = 22.13 m /s

d )

apparent weight

mg - mv² / R

= 882 - (882 / 9.8 )x 22.13²/50

= 882 + 882

= 1764 N

6 0

2 years ago

HELP PLS i need this right now

N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

$V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }$

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

$V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units$

7 0

3 years ago

I need helpppppppppppppppppp!

allsm [11]

Answer:

i think its B

Explanation:

but check it before do it

3 0

3 years ago

Read 2 more answers

A printed circuit board (PCB) is supported by a chassis that is attached to a vibrating motor. The board is 1.6 mm thick, 200 mm

Vedmedyk [2.9K]

jtejyrkekdkeludmydmumud

5 0

2 years ago

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece

Brilliant_brown [7]

Answer:

10.01 cm

Explanation:

Given that,

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.

The average propagation speed for sound in body tissue is 1540 m/s.

We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

$v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1540\times 0.13\times 10^{-3}}{2}\\\\d= $$0.1001\ m$

d = 10.01 cm

So, the reflection will occur at 10.01 cm.

8 0

2 years ago