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2 years ago

5

What is the SI unit for momentum? kg•m kg•m/s kg•m²/s Kg•m/s^2

1 answer:

stepan [7]2 years ago

4 0

Answer:Kg•m/s

Explanation:the SI unit for momentum is kg•m/s

Momentum=mass x velocity

Unit for mass=kg

Unit for velocity=m/s

Therefore they unit for momentum is kg•m/s

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Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250

m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = $\dfrac{\pi}{4}d^2$

v = Terminal velocity = $v=210\ m/s$

s = Displacement = 150 m

$a=\dfrac{v^2-u^2}{2s}$

Force is given by

F = ma

$F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622$

The drag coefficient is 0.363999909622 (ignoring negative sign)

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3 years ago

You need to produce a set of cylindrical copper wire 3.5 m long that will have a

vazorg [7]

Solution :

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Now, we know mass of wire is given by :

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Hence, this is the required solution.

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