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3 years ago

What is the SI unit for momentum? kg•m kg•m/s kg•m²/s Kg•m/s^2

Physics

1 answer:

stepan [7]3 years ago

4 0

Answer:Kg•m/s

Explanation:the SI unit for momentum is kg•m/s

Momentum=mass x velocity

Unit for mass=kg

Unit for velocity=m/s

Therefore they unit for momentum is kg•m/s

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The drawing shows an equilateral triangle, each side of which has a length of 2.00 cm. Point charges are fixed to each corner, a

Kipish [7]

Answer:

$-2.60097\times 10^{-6}\ C$

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

r = Distance between charges = 2 cm

The electric force is given by

$F=\dfrac{k4\times 10^{-6}q_A}{r^2}$

Also

$F=\dfrac{k4\times 10^{-6}q_B}{r^2}$

The sum of the force is given by

$\sum F=\dfrac{k4\times 10^{-6}q_A}{r^2}cos 30+\dfrac{k4\times 10^{-6}q_B}{r^2}cos 30\\\Rightarrow \sum F=2\dfrac{k4\times 10^{-6}q_A}{r^2}cos 30\\\Rightarrow q_a=\dfrac{\sum Fr^2}{2\times k4\times 10^{-6}cos30}\\\Rightarrow q_a=\dfrac{405\times 0.02^2}{2\times 8.99\times 10^9\times 4\times 10^{-6}cos30}\\\Rightarrow q_a=2.60097\times 10^{-6}\ C$

Thus $q_a=q_b=-2.60097\times 10^{-6}\ C$ .

The negative sign is because the force points downward which is taken as negative

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4 years ago

A playground merry-go-round of radius r = 1 m has a moment of inertia of i = 240 kg*m^2. and is rotating at a rate of ω = 8 rev/

Ghella [55]

When the child jumps onto the merry-go-around the moment of inertia of the system changes. If we consider the child to be point-like mass then its moment of inertia would be:
$I_{ch}=mr^2$
We get the new moment of inertia by simply adding the child's moment of inertia to the old moment of inertia.
$I_{new}=I_{old}+I_{ch}=240+35(1)^2=275 $kgm^2$
Since there is no force mention we must assume that angular momentum is conserved.
$L=const.\\ L=I_{old}\omega_0=I_{new}\omega'\\ \omega'=\frac{I_{old}\omega_0}{I_{new}}$
When we plug in all the numbers we get:
$\omega'=\frac{240\cdot8}{275}=6.98 \ \frac{rev}{min}$

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3 years ago

A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance

FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

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The answer would be
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