1) The distance travelled by the electron is 
2) The time taken is 
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:

2)
The total time taken for the electron in its motion can also be found by using another suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have

v = 0

And solving for t, we find the time taken:

Learn more about accelerated motion:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
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