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Ivanshal [37]
1 year ago
15

A 20-liter container contains 2.0 moles of oxygen at a pressure of 92 kpa. the average kinetic energy of translation of oxygen m

olecules in the gas is:_______
Physics
1 answer:
Vikentia [17]1 year ago
4 0

From ideal gas law, PV=nRT

where P is the pressure, V is the volume of the container, n is number of moles, R is the gas constant and T is the temperature.

Hence, T=\frac{PV}{nR}=\frac{92*10^{3}*2.0*10^{-3}}{2*3.314}

T= 110.65 k

Kinetic Energy = \frac{3}{2}KT=\frac{3}{2}  (1.38*10^{-23})(110.65)

K.E=  2.2*10^{-21}J

<h3>What is a kinetic energy? </h3>

The energy an object has as a result of motion is known as kinetic energy.

A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transferred and is dependent on the mass and speed attained.

Kinetic energy can be converted into other types of energy and transported between objects. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's initial kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the collision.

To know more about kinetic energy, visit:

brainly.com/question/22174271

#SPJ4

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What is an accurate definition of a heat engine?
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A ford F-250 pulls a 1000-kg car with a net force of 2000 N. What is the acceleration of the car A=F/m
vfiekz [6]

Answer:

2ms^2

Explanation:

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5 0
3 years ago
Two identical light springs with spring constant k3 are now individually hung vertically from the ceiling and attached at each e
Alenkasestr [34]

Answer:

 Keq = 2k₃

Explanation:

We can solve this exercise using Newton's second one

                F = m a

Where F is the eleatic force of the spring F = - k x

Since we have two springs, they are parallel or they are stretched the same distance by the object and the response force Fe is the same for the spring age due to having the same displacement

          F + F = m a

         k₃ x + k₃ x = m a

         a = 2k₃  x / m

To find the effective force constant, suppose we change this spring to what creates the cuddly displacement

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7 0
3 years ago
A 17500 kg jet airplane is flying through some high winds. At some point in time, the airplane is pointing due north, while the
Yuri [45]

Answer:

The magnitude of the acceleration is 1.34 m/s².

The direction of acceleration is 77.9° clockwise with west.

Explanation:

Given that,

Mass of jet = 17500 kg

Force on the plane = 36500 N due north

Force from the wind =14500 N

Angle = 75.0°

We need to calculate the net force on jet plane

Using formula of net force

F=36500\hat{j}+14500(-\cos70^{\circ}\hat{i}-\sin70^{\circ}\hat{j})

We need to calculate the acceleration

a=\dfrac{36500\hat{j}+14500(-\cos70^{\circ}\hat{i}-\sin70^{\circ}\hat{j})}{17500}

a=\dfrac{36500 j}{17500}+(\dfrac{-4959.29\ i}{17500}-\dfrac{13625.54\ j}{17500})

a=-0.28\ i+1.307\ j

The magnitude of the acceleration

a=\sqrt{(0.28)^2+(1.307)^2}

a=1.34\ m/s^2

We need to calculate the direction of the acceleration

Using formula of the direction

\tan\theta=\dfrac{j}{i}

Put the value into the formula

\tan\theta=\dfrac{1.307}{0.28}

\theta=\tan^{-1}\dfrac{1.307}{0.28}

\theta=77.9^{\circ}

The direction of acceleration is 77.9° clockwise with west.

Hence, The magnitude of the acceleration is 1.34 m/s².

The direction of acceleration is 77.9° clockwise with west.

5 0
3 years ago
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