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3 years ago

A mass weight of 120N is hung from two strings. what is the tension?

Physics

2 answers:

I am Lyosha [343]3 years ago

8 0

Answer: $T_1 = 77.2 \text N \newline T_2= 91.87 \text N$

Assuming the figure as attached.

The sum of Horizontal components of the Tension in the rope is zero or equal as they balance out each other. $T_1 sin40 \textdegree = T_2 sin50 \textdegree \newline T_1 = 1.19 T_2$

The sum of vertical components of the tension is equal to the weight of the block. $T_1 cos 40 \textdegree +T_2cos50 \textdegree = 120 \text N \newline 1.19T_2(0.766 )+T_2 0.64 = 120 \text N T_2 = 77.2 \text N T_1 = 1.19 T2 = 1.19 \times 77.2 \text N = 91.87 \text N$

kramer3 years ago

7 0

The weight should be shared between the two string equally. Therefore, tension in each string, T is;

T = 120 N/2 = 60 N

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pav-90 [236]

I attached the missing picture.
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
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$F_a=F_cf-F_g$
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At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
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Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance:
$F_g=F_{cf}\\
mg=m\frac{v^2}{r}\\
gr=v^2\\
v=\sqrt{gr}=8.29\frac{m}{s}$

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