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4 years ago

A mass weight of 120N is hung from two strings. what is the tension?

Physics

2 answers:

I am Lyosha [343]4 years ago

8 0

Answer: $T_1 = 77.2 \text N \newline T_2= 91.87 \text N$

Assuming the figure as attached.

The sum of Horizontal components of the Tension in the rope is zero or equal as they balance out each other. $T_1 sin40 \textdegree = T_2 sin50 \textdegree \newline T_1 = 1.19 T_2$

The sum of vertical components of the tension is equal to the weight of the block. $T_1 cos 40 \textdegree +T_2cos50 \textdegree = 120 \text N \newline 1.19T_2(0.766 )+T_2 0.64 = 120 \text N T_2 = 77.2 \text N T_1 = 1.19 T2 = 1.19 \times 77.2 \text N = 91.87 \text N$

kramer4 years ago

7 0

The weight should be shared between the two string equally. Therefore, tension in each string, T is;

T = 120 N/2 = 60 N

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House current is 120 volts. If a light bulb runs a current of 10 amps, what is the resistance?

nlexa [21]

Answer:

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Explanation:

Ohm's Law tells the relationship between voltage, current, and resistance.

It can be written in three different ways, depending on which ones you know,

and which one you want to find.

Here's the one we need:

Resistance = (voltage) divided by (current)

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6 0

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Vinvika [58]

Answer:

The phase angle is 0.0180 rad.

(c) is correct option.

Explanation:

Given that,

Voltage = 12 V

Angular velocity = 50 Hz

Capacitance $C= 20\times10^{-2}\ F$

Inductance $L=20\times10^{-3}\ H$

Resistance $R= 50\ Omega$

We need to calculate the impedance

Using formula of impedance

$z=\sqrt{R^2+(\omega L-\dfrac{1}{\omega C})^2}$

$z=\sqrt{50^2+(50\times20\times10^{-3}-\dfrac{1}{50\times20\times10^{-2}})^2}$

$z=50.00$

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Using formula of phase angle

$\theta=\cos^{-1}(\dfrac{R}{z})$

$\theta=\cos^{-1}(\dfrac{50}{50.00})$

$\theta=0.0180\ rad$

Hence, The phase angle is 0.0180 rad.

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Answer:

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Explanation:

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