Question

A mass weight of 120N is hung from two strings. what is the tension?

Answer 1

Answer: $T_1 = 77.2 \text N \newline T_2= 91.87 \text N$

Assuming the figure as attached.

The sum of Horizontal components of the Tension in the rope is zero or equal as they balance out each other.$T_1 sin40 \textdegree = T_2 sin50 \textdegree \newline T_1 = 1.19 T_2$

The sum of vertical components of the tension is equal to the weight of the block.$T_1 cos 40 \textdegree +T_2cos50 \textdegree = 120 \text N \newline 1.19T_2(0.766 )+T_2 0.64 = 120 \text N T_2 = 77.2 \text N T_1 = 1.19 T2 = 1.19 \times 77.2 \text N = 91.87 \text N$

Answer 2

The weight should be shared between the two string equally. Therefore, tension in each string, T is;

T = 120 N/2 = 60 N