Question

1. A 0.250 kg baseball sits on the ledge of a window in Treadwell hall. If the ball has 18.5

Answer 1

Answer:

h = 7.54 m

t = 1.24 s

Explanation:

1.Let g = 9.81 m/s2 is the gravitational acceleration. Since the formula for potential energy is:

$E_p = mgh$

where m = 0.25 is the ball mass and h is the height. We can solve for h

$h = \frac{E_p}{mg} = \frac{18.5}{0.25*9.81} = 7.54m$

2. The time it take for the ball to reach a distance of 7.54m with a gravitational acceleration of 9.81m/s2:

$h = \frac{gt^2}{2}$

$t^2 = \frac{2h}{g} = \frac{2*7.54}{9.81} = 1.54$

$t = \sqrt{1.54} = 1.24 s$