A metal rod A and a metal sphere B, on insulating stands, touch each other. They are originally neutral. A positively charged ro
1 answer:
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The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.
<h3>What mass of lead should be placed on the cube?</h3>
Given: Side of the cube (a) = 20cm
The density of the cube (ρc) =
a) Applying the force balance, the buoyant force must be equal to the weight of the cube
ρcgV = ρg × (Ax)
Substituting the values in the above equation, we get
x = 0.13
where x is the height of the cube in the water
is the area of the cross-section
ρ is the density of the water
V is the volume of the cube
Now, the height above the surface of the water would be
h = a − x
Substituting the values, then we get
h = 0.2 − 0.13
h = 0.07 m
b) The mass added is "m" so the complete cube is submerged in the water, therefore
ρcgV + mg = ρg × (V)
m = 2.8 kg
The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.
To learn more about buoyant force refer to:
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Answer:
Explanation:
From the question we are told that:
Number of battery
Voltage source
Lamp Power
Generally the equation for Resistance is mathematically given by
Therefore
Generally the equation for Current is mathematically given by
The answer is in the attachment
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Answer:
The approximate change in entropy is -14.72 J/K.
Explanation:
Given that,
Temperature = 22°C
Internal energy
Final temperature = 16°C
We need to calculate the approximate change in entropy
Using formula of the entropy
Where, = internal energy
T = average temperature
Put the value in to the formula
Hence, The approximate change in entropy is -14.72 J/K.