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3 years ago

10

A boat leaves a dock at 7:00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15 km/h a

nd reaches the same dock at 8:00 pm. how many minutes after 7:00 pm were the two boats closest together? (round your answer to the nearest minute.)

1 answer:

xxMikexx [17]3 years ago

7 0

Zero minute
Because the traveling boat is faster .
And this is my answer

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According to Newton´s second law of motion, what does an object with more mass require? Question 8 options:

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Explain what does a calorimeter measure?

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Measuring the heat of chemical reactions or physical changes.

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Which equation represents the total energy of a system?

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C) Total Energy = Potential Energy + Kinetic Energy

Explanation:

The total energy of a system (also called mechanical energy) is given by:

$E=PE+KE$

where

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KE is the kinetic energy

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3 years ago

A car mass 600kg starts from rest moving uniform acceleration 0.2 m/s^2 after 60 seconds collides with stationary pick up van of

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Answer:

the phenomenon of the system supports the principle of conservation of momentum.

Explanation:

The law of conservation of momentum says that:

Initial Momentum = Final Momentum

So, first we calculate initial momentum of the system:

Initial Momentum = m₁u₁ + m₂u₂

where,

m₁ = mass of car = 600 kg

m₂ = mass of van = 400 kg

u₁ = Initial Speed of Car

For initial speed of car, we use:

Vf = Vi + at

Vf = 0 m/s + (0.2 m/s²)(60 s)

Vf = u₁ = 12 m/s

u₂ = Initial Speed of Van = 0 m/s

Therefore,

Initial Momentum = (600 kg)(12 m/s) + (400 kg)(0 m/s)

Initial Momentum = 7200 Ns --------------- equation (1)

Now, for the final momentum:

Final Momentum = m₁v₁ + m₂v₂

where,

v₁ = v₂ = Final Speed of Car and van (both are locked) = 7.2 m/s

Therefore,

Final Momentum = (600 kg)(7.2 m/s) + (400 kg)(7.2 m/s)

Final Momentum = 7200 Ns ------------- equation (2)

Comparing equation (1) and (2):

Initial momentum = Final Momentum

<u>Hence, the phenomenon of the system supports the principle of conservation of momentum.</u>

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A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is

Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration $a_{c}$ is given by the following equation:

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Where:

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Isolating $V$ from (1):

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$V=\sqrt{(17 m/s^{2})(12 m)}$

<u />

Finally:

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