Question

our friend claims that his commute time to work is less than his commute time returning home on the same day. suppose that data were collected for a random set of 11 days, where each difference is calculated by subtracting the commute time to work from the commute time returning home. assume that the populations are normally distributed. suppose the test statistic is computed to be t≈−1.788, with 10 degrees of freedom. what range contains the p-value?

Answer 1

Using a t-distribution calculator, the p-value is of 0.052, hence the range that contains the p-value is an interval between a number less than 0.05 and a number greater than 0.05.

How to find the p-value of the t-distribution?

To find the p-value of the t-distribution, three information, which are the inputs on the calculator are needed:

• The test statistic.

• The number of degrees of freedom.

• The tail of the test.

In this problem, we have that:

• The test statistic is of t = -1.788.

• The number of degrees of freedom is of 10.

• We are testing if the mean is less than a value, hence we have a left-tailed test.

Hence, using a calculator, it is found that the p-value is of 0.052, hence the range that contains the p-value is an interval between a number less than 0.05 and a number greater than 0.05.

More can be learned about the t-distribution at brainly.com/question/13873630

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