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Elodia [21]
1 year ago
13

Calculate each of the following quantities: (a) Total number of ions in 38.1 g of SrF₂

Chemistry
1 answer:
adelina 88 [10]1 year ago
8 0

The total number of ions in 38.1 g of SrF₂ is 5.479 x 10²³.

<h3>What are ions?</h3>

Ions are the elements with a charge on them. It happens when they share electrons with other atoms to form a compound.

We have to calculate the total number of ions in 38.1 g of .

The molar mass of SrF₂ = 125.62 g/mol

The number of moles = 38.1 g of  1.0 mol / 125.62  = 0.30329 moles

Given that, total moles of SrF₂ ions in  = 1.0 mol of + 2.0 moles of  = 3.0 moles

Total moles of ions in 0.30329 moles of

= (0.30329 moles of SrF₂) x 3.0 / 1.0  = 0.90988 mol ions

We know that,

1.0 mole of ions = 6.023 x 10²³ ions

Thus, the number of total ions = ( 0.90988 mol ions) x  6.023 x 10²³ / 1.0 mol = 5.479 x 10²³ ions

Thus, the number of ions is in 38.1 g of 5.479 x 10²³ ions

To learn more about ions, refer to the link:

brainly.com/question/14295820

#SPJ4

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Answer: 45.983 g CBr₄

Explanation:

To convert from moles to grams, you know that we will need molar mass and Avogadro's number.

Avogadro's number: 6.022×10²³ molecules/mol

Molar mass: 331.627 grams/mol

Now that we have what we need, you can use these to solve for grams. 8.35*10^2^2molecules CBr_{4} *\frac{1mol}{6.022*10^2^3molecules} *\frac{331.627 g}{1 mol} =45.983 g

Our final answer is 45.983 g CBr₄.

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