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4 years ago

How many hydrogen atoms are in 2NH3

Chemistry

2 answers:

Nuetrik [128]4 years ago

5 0

There are 3 hydrogen atoms.

Natalka [10]4 years ago

3 0

There would be 3 hydrogen atoms and you can check because the number to the right of the atom tells you how many atoms of that there are assuming it's down low

You might be interested in

What mass of S8 will completely react with 167.6 grams of Fe?

IRISSAK [1]

Answer:
mass of S₈ = 96.1146 grams

Explanation:
The balanced equation that describe the reaction is as follows:
8 Fe + S₈ ..............> 8 FeS

From the equation, we can note that:
8 moles of Fe react with 1 mole of S₈
This means that:
8 * 55.8 grams of iron react with 8 * 32 grams of S₈.
To know the mass of S₈ that will react with 167.6 grams of Fe, we will simply do cross multiplication as follows:
mass of S₈ = (167.6 * 8 * 32) / (8 * 55.8)
mass of S₈ = 96.1146 grams

Hope this helps :)

5 0

3 years ago

How many grams are in 6.02E23 atoms of carbon?

Oksanka [162]

Answer:

no sure

Explanation:

8 0

3 years ago

How many atoms are in 25.00 g of B?

klio [65]

Answer:

There are 1.393 x 10²⁴ atoms in 25.00 g of B.

Explanation:

Hey there!

We are given a value, in grams, that we need to convert to a number of atoms.

We can convert grams to atoms by using Avogadro's Number ( $N_A$ ). This number is equivalent to $6.022 \times 10^{23}$ .

This number can be used to convert any values to:

atoms
molecules
formula units
moles

In order to do this problem, we will need to use dimensional analysis (DA). This process allows us to convert from grams to atoms.

We need to set up our ratios in order to work this out. We can use a periodic table to help us through this next part of the problem.

1. Locating the number of moles of B in the sample

We first need to find the amount of moles of boron (B) there are in the sample.

Checking a periodic table, the atomic mass in atomic mass units (amu) is 10.81 amu.

Atomic mass units can easily be converted to grams and these units can be used interchangeably.

Therefore, for each atom of boron, it weighs 10.81 grams to us. This is equivalent to the mass of one mole of boron.

To find the number of moles, we have two possible ratios we can use:

$\displaystyle \frac{1 \ mole \ B}{10.81 \ grams \ B}$

$\displaystyle \frac{10.81 \ grams \ B}{1 \ mole \ B}$

These ratios mean the same thing, but we need to convert our final unit to moles.

We are given a sample in grams, and when dividing our units, we need to keep moles.

Since the first portion of our expression is in grams, we need to have grams in the bottom of our expression.

$\displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}}$

We can now simplify the expression. Our grams B unit will cancel out, so we are therefore left with moles B remaining.

2. Locating the number of atoms in the sample

Now with our equation, we can convert our number of moles that would be solved if we stopped with the above. However, we need to convert to atoms.

We use Avogadro's number and create a ratio with that of moles.

$\displaystyle \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}$

$\displaystyle \frac{1 \text{mole B}}{6.022 \times 10^{23} \text{atoms}}$

We need to cancel out our moles and end with atoms, so we must have moles in the denominator. Therefore, we use the first ratio.

Using our previous expression, we multiply by this new ratio and solve the expression.

$\displaystyle 25.00 \ \text{grams B} \ \times \frac{1 \text{mole B}}{10.81 \ \text{grams B}} \ \times \frac{6.022 \times 10^{23}\text{atoms}}{1 \text{mole B}}$