Respuesta:
340 N/cm²
Explicación:
Paso 1: Información provista
Peso de la estructura (F): 8500 Newton
Area superficial (A): 25 cm²
Paso 2: Calcular la presión (P) ejercida por la estructura de concreto sobre su base
La presión es igual al cociente entre la fuerza ejercida y la superficie sobre la que se aplica.
P = F/A
P = 8500 N / 25 cm² = 340 N/cm²
Answer:
The required ratio would be 2:1
Answer:
solute
Explanation:
The substance that dissolves is called the solute. The substance that dissolves it is called the solvent.
We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:
ATP + H₂O → ADP + HPO₄²⁻
We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:
ΔGrxn = ΔG°rxn + RTlnQ
We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:
Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001
Now we can use the above formula to solve for ΔGrxn.
ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol
The value of ΔGrxn = -54.3 kJ/mol.
Answer:
0.57 moles (NH4)3PO4 (2 sig. figs.)
Explanation:
To quote, J.R.
"Note: liquid ammonia (NH3) is actually aqueous ammonium hydroxide (NH4OH) because NH3 + H2O -> NH4OH.
H3PO4(aq) + 3NH4OH(aq) ==> (NH4)3PO4 + 3H2O
Assuming that H3PO4 is not limiting, i.e. it is present in excess
1.7 mol NH4OH x 1 mole (NH4)3PO4/3 moles NH4OH = 0.567 moles = 0.57 moles (NH4)3PO4 (2 sig. figs.)"
