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4 years ago

Which element and how many atoms does each compound have in the picture?

Chemistry

1 answer:

Stells [14]4 years ago

7 0

The first one has 35 atoms and the elements hydrogen, oxygen and chlorine

The second one has 9 atoms and the elements sodium, carbon, and helium

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How many moles of water are produced in the complete combustion of 2.5 L of methanol (CH3OH) at STP?

alexgriva [62]

Hope this helps you!

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3 years ago

Deuterium (D or 2H) is an isotope of hydrogen. The molecule D2 undergoes an exchange reaction with ordinary hydrogen, H2, that l

Paladinen [302]

Answer:

$Kp_2} =2.0$

Explanation:

$K_{p1}= 1.8$

$K_{p2}= ???$

$T_1= 298K$

$T_2 = 415 K$

$\delta H$ = 0.64 kJ/mol = 640 J/mol

R = 8.314 J/mol.K

Using Van't Hoff Equation:

$In (\frac{Kp_2}{Kp_1} )=(-\frac{DH}{R} *(\frac{1}{T_2}-\frac{1}{T_1} )$

$In (\frac{Kp_2}{1.8} )=(-\frac{640}{8.314} *(\frac{1}{415}-\frac{1}{298} )$

$In (\frac{Kp_2}{1.8} )=0.072827$

$(\frac{Kp_2}{1.8} )= e^{0.0728727}$

$\frac{Kp_2}{1.8} =1.075593605$

$Kp_2} =1.075593605*1.8$

$Kp_2} =1.936068489$

$Kp_2} =2.0$

3 0

3 years ago

Read 2 more answers

How many grams of calcium bromide are in 50.0 mL of a 0.25 M calcium bromide solution?

lianna [129]

$C_{m}=\frac{n}{V_{r}}\\\\
m=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV_{r}} \ \ \ \ \Rightarrow \ \ \ \ m=C_{m}MV_{r}}\\\\
C_{m}=0.25\frac{mol}{L}\\
M_{CaBr_{2}}=200\frac{g}{mol}\\
V_{r}=50mL=0.05L\\\\
m=0.25\frac{mol}{L}*200\frac{g}{mol}*0.05L= \emph{\textbf{2.5g}}$

8 0

3 years ago

Calculate the moles of oxygen gas which will react with 89.4 grams of iron.

Snowcat [4.5K]

<span>No of moles of Fe = Mass / Relative molar mass of Fe. So no of moles = 89.4/ 55.845 = 1.60. The. Chemical reaction is represented as follows. 4 Fe + 3 O2 which gives 2Fe2 O3 . This means that 4 atoms of Iron reacts with 3 atoms of Oxygen to produce Iron oxide. Hence 1.60*4 moles of Fe will need to react 1.6 * 3 moles of Oxygen to produce 2 moles of Iron oxide. Hence 4.8 moles of Oxygen will be required.</span>

3 0

3 years ago

Consider the balanced chemical equation: 2o3(g) → 3o2(g). how many moles of o2 are produced when 0.50 mol of o3(g) reacts

kiruha [24]

2O3→3O2
The number of moles of O2 that are produced when 0.50 moles of O3(g) reacted is 0.75 moles

calculation and explanation

2 moles of O3(ozone) react to give 3 moles of O2 (oxygen gas,therefore the reacting ratio between O3 :O2 is 2:3

if 0.50 moles of O3 reacted then,by use of reacting ratio (2:3) find the moles of O2 produced

That is 0.50 x3/2 = 0.75 moles

7 0

3 years ago