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Andrei [34K]
2 years ago
6

In how many ways can the elements of [n] be permuted if 1 must precede 2 and 3 is to precede 4?

Physics
1 answer:
sp2606 [1]2 years ago
4 0

No. of ways in the elements of n be permuted is  n!/4

Number of elements = n

Number of face in which the element of n be permuted if 1 must proceed 2 and 3 is to precede 4.

n =  4

The possible permutation will

(1,2,3,4), (1,3,2,4),(1,3,4,2),(3,4,1,2),(3,1,2,4),(3,1,4,2)

There are 6 possible outcomes

For n= 5

With 1,2,3,4 we add 5 in the arrangement with above terms

The possible number of permutation

5×6 = 30

When n = 6

30×6 = 180.

So for an element

If 1 precede 2 and 3 is yo precede 4 is

<h2>\frac{n*(n-1)*(n-2) ........ 6*5*6*4!}{4!}</h2>

= n! ×6/4!

= n!/4

No. of ways in the elements of n be permuted is  n!/4

To know more about permutation:

brainly.com/question/4416319

#SPJ4

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The speed limit on some interstate highways is roughly 80 km/h. What is this in meters per second? How many miles per hour is th
sergey [27]

Answer:

1) Speed in m/s equals 22.22 m/s.

2) Speed in miles per hour equals 49.712 mph.

Explanation:

Since we know that in 1 kilometer there are 1000 meters and in 1 hour there are 3600 seconds hence we can write

80km/h=\frac{80\times 1000m}{3600s}=22.22m/s

Now we know that 1 mile equals 1.609 kilometer  hence we conclude that 1 kilometer equals \frac{1}{1.609}=0.6214mile

Hence

80km/h=\frac{80\times 0.6214miles}{1h}=49.712mph

3 0
4 years ago
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
Liono4ka [1.6K]

Answer:

The answer is below

Explanation:

The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:

h=\frac{u^2sin^2\theta}{2g}

Given that the two projectile has the same height.

For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}

8 0
3 years ago
For an object moving with constant negative acceleration, draw the following:
Tcecarenko [31]

Answer:

Kindly find the graphs attached

Explanation:

For figure 1: There is a steady increase in the position of the object as time increases. This is because despite the negative acceleration (deceleration), the object continues to move and cover more ground as time goes by.

<em>The straight line graph is observed because the acceleration is constant  and not varying.</em>

For Figure 2: The graph of velocity vs time will have an inverted nature. This is because since the object is decelerating, it is reducing in its velocity as time goes by (increases). <em>This is also in a straight line since the deceleration is constant.</em>

3 0
3 years ago
Which statement best describe one of George Berkeley's arguments against materialism?
sasho [114]

Answer:

the answer is B

Explanation:

materialism is just wanting to always buy new things B does the opposite

5 0
3 years ago
If the momentum of a 1000 kg car travelling at 10 m/s was transferred completely to a 20.0 kg traffic barrier, what would the fi
denis-greek [22]

Answer:

d. 500 m/s

Explanation:

Momentum: This is the product of the mass of a body to its velocity, The S.I unit of momentum is kgm/s.

Mathematically, momentum can be expressed as,

M = mv....................... equation 1

Where M = momentum, m = mass, v = velocity

deduced from the question,

Momentum of the car = momentum of the barrier.

MV = mv ............................. Equation 1

Where M = mass of the car, V = velocity of the car, m = mass of the barrier, v = velocity of the barrier.

making v the subject of the equation,

v = MV/m........................ Equation 2

Given: M = 1000 kg, V = 10 m/s, m = 20 kg.

Substitute into equation 2

v = 1000(10)/20

v = 500 m/s.

Hence the speed of the barrier = 500 m/s

The right option is d. 500 m/s

8 0
4 years ago
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