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Nadusha1986 [10]
4 years ago
9

Which scientist discovered the two radioactive elements radium anf polonium

Physics
2 answers:
jeka57 [31]4 years ago
8 0
Pierre curie was the one who discovered radium
cricket20 [7]4 years ago
7 0

Answer:

Marie Curie & Pierre Curie

Explanation:

Marie Curie along with her husband Pierre Curie was studying the radioactivity of pitchblende, (also called uranite), the uranium ore

They found that the radioactivity of the pitchblende was radioactive even after removing Uranium and Thorium from it.

In July 1898 they isolated polonium from pitchblende and in December 1898 they isolated radium from pitchblende.

They named polonium after Poland, the homeland of Marie Curie.

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Describe at least two ways that electromagnet force and weak nuclear forces are alike and two ways that they are different.
ruslelena [56]

Different: The weak nuclear force is responsible for radioactive decay within an atom of a substance, while the electromagnetic force causes electrostatic force between charged particles.


Different: The weak force has a very small range of effectiveness (where the force can be felt) while the electromagnetic force has an infinite range.


Same: Both forces act within an nucleus, or on a nuclear level.


Same: The weak nuclear force is mediated by charged particles called bosons, and the electrostatic force is only present within charged objects


The last one may be a bit of a stretch but I hope this helped a bit!

4 0
3 years ago
A toddler pushed a 4-kg toy car at a constant speed against a ground frictional force of 8 N.
Soloha48 [4]
Correct me if I’m wrong but I think it’s C
4 0
3 years ago
A circular coil of wire, with N turns of radius a, is located in the field of an electromagnet. The magnetic field is perpendicu
weeeeeb [17]

Answer:

they are going to attract

Explanation:

7 0
3 years ago
Which statement about coal is true? When burned, coal produces pollutants that are released into the air. Coal will always stay
Svetllana [295]
2, coal is a renewable resource
7 0
3 years ago
A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.
antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0
3 years ago
Read 2 more answers
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