Answer:
A.−2.1 × 10^10 N
Explanation:
Using the formula;
E = k Q1Q2/d²
Where;
E is the electrical force
k is the constant
Q1, Q2 are the two charges and
d is the distance between the two charges
Therefore;
E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²
= -2.1 x 10^10 N
Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.
Depends on the elasticity and density of the medium through what it is traveling <span> </span>
Well, it is not ultraviolet rays and I highly doubt it is visible light. I would say gamma rays. Hope this helps! :)
Answer:
the correct answer would be B. have a good day!
Explanation: