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sesenic [268]
3 years ago
13

How does Dr.Hoffmann's ultrasound device benefit society? ( modern chemistry textbook page 180).

Chemistry
2 answers:
Masja [62]3 years ago
7 0
<span> She developed new models for emergency ultrasound education and competency assessment, created a successful emergency ultrasound fellowship program, and introduced electronic </span>workflow<span> solutions to </span>Hopkins<span>, increasing the use of emergency ultrasound by 7-fold.</span>
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

In 1966, Dr. Hoffmann recorded for the first time in medicine embryonic movements and the heartbeat of the fetus using an ultrasound system.

Explanation:

Today, ultrasound is a technique widely used by many medical specialties, in the emergency department, in intensive care or in daily practice.

In 1794, the Italian Spallanzani observed that during the flight of bats they did not collide with anything despite being blind. It is then that he theorizes that they emitted sounds imperceptible to the man he would call ultrasounds, which they capture with their ears after bouncing off objects.

In 1842, Christian Doppler's first article on the effect of his name appears.

In 1912, Richardson suggests the use of ultrasonic echoes to detect submerged objects, creating the first ultrasonic generator five years later by Paul Langevin and Chilowsky.

Since then the applications of this new technology have been unstoppable, especially in medicine.

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you find that 7.36g of a compound has decomposed to give 6.93g of oxygen. the only other element in the compound is hydrogen. if
slavikrds [6]
First solve the moles of oxgen present in the compound

mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H

then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
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3 years ago
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How do you find the volume of a liquid
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3 years ago
What is the purpose of the stairstep pattern on the periodic table of the elements?
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Answer: The bold staircase in the periodic table allows us to classify which elements are metalloids.

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3 years ago
Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe
Illusion [34]

Answer:

a. Kp=1.4

P_{A}=0.2215 atm

P_{B}=0.556 atm

b.Kp=2.0 * 10^-4

P_{A}=0.495atm

P_{B}=0.00995 atm

c.Kp=2.0 * 10^5

P_{A}=5*10^{-6}atm

P_{B}=0.9999 atm

Explanation:

For the reaction  

A(g)⇌2B(g)

Kp is defined as:

Kp=\frac{(P_{B})^{2}}{P_{A}}

The conditions in the system are:

          A                    B

initial   0                1 atm

equilibrium x       1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.    

Replacing these values in the expression for Kp we get:

Kp=\frac{(1-2x)^{2}}{x}

Working with this equation:

x*Kp=(1-2x)^{2} - -> x*Kp=4x^{2}-4x+1- - >4x^{2}-(4+Kp)*x+1=0

This last expression is quadratic expression with a=4, b=-(4+Kp) and c=1

The general expression to solve these kinds of equations is:

x=\frac{-b(+-)*\sqrt{(b^{2}-4ac)}}{2a} (equation 1)

We just take the positive values from the solution since negative partial pressures don´t make physical sense.

Kp = 1.4

x_{1}=\frac{(1.4+4)+\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=1.128

x_{1}=\frac{(1.4+4)-\sqrt{(-(1.4+4)^{2}-4*4*1)}}{2*4}=0.2215

With x1 we get a partial pressure of:

P_{A}=1.128 atm

P_{B}=1-2*1.128 = -1.256 atm

Since negative partial pressure don´t make physical sense x1 is not the solution for the system.

With x2 we get:

P_{A}=0.2215 atm

P_{B}=1-2*0.2215 = 0.556 atm

These partial pressures make sense so x2 is the solution for the equation.

We follow the same analysis for the other values of Kp.

Kp=2*10^-4

X1=0.505

X2=0.495

With x1

P_{A}=0.505atm

P_{B}=1-2*0.505 = -0.01005 atm

Not sense.

With x2

P_{A}=0.495atm

P_{B}=1-2*0.495 = 0.00995 atm

X2 is the solution for this equation.  

Kp=2*10^5

X1=50001

X2=5*10^{-6}

With x1

P_{A}=50001atm

P_{B}=1-2*50001=-100001atm

Not sense.

With x2

P_{A}= 5*10^{-6}atm

P_{B}=1-2*5*10^{-6}= 0.9999 atm

X2 is the solution for this equation.  

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3 years ago
A man drove his car through the Nevada desert one day when the temperature was over 100°F. When he started the trip, the gas sta
Slav-nsk [51]
<span>The temperature in the tire increased, causing an increased tire pressure. :D</span>
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3 years ago
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