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murzikaleks [220]
1 year ago
12

reggie drew a scale drawing of a swimming pool. the scale of the drawing was 4 millimeters : 3 meters. the pool is 24 meters lon

g in real life. how long is the pool in the drawing?
Mathematics
1 answer:
Shkiper50 [21]1 year ago
6 0

The pool that Reggie drew will be 24 millimeters long, compare to real life which is 24 meters long.

As we can't create a real-life dimension in a small sheet of paper, we opted for a small scale that covers up the large length. As we are given, the scale of the drawing is 4 millimeters: 3 meters, which means 1 millimeter is equal to 3/4 meters, and the size of the pool in real life is 24 meters.

So, the length of the pool in the drawing is = 24*(3/4)

                                                                           = 24 millimeters

To know  more about scale manipulation refer to the link brainly.com/question/14806083?referrer=searchResults

#SPJ4

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Step-by-step explanation:
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6 0
3 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

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