Answer:
The atom economy of ethane in this process is 19.72 %.
What is atom economy?
The conversion efficiency of a chemical reaction in terms of all the atoms involved and the desired products produced is known as atom economy (atom efficiency/percentage).
Explanation:
C₁₀H₂₂ → C₈H₁₈ + C₂H₄
Molecular weight of C₁₀H₂₂ = 142.28
Molecular weight of C₈H₁₈ = 114.228
Molecular weight of C₂H₄ = 28.053
% Atom economy = 
= 
= 19.716 %
≈ 19.72 %
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Answer:
Sr would be the limiting reactant
5 moles
Explanation:
Since the equation is a balanced equation, the coefficient shows how each substance relates to the other in terms of the number of moles.
Reactants would be those on the left hand side of the arrow, while the products would be found on te right and side of the arrow. In this question, the reactants would be Sr and O₂.
Limiting reactant is the reactant that is insufficient; meaning to say that there is not enough of that substance and thus the reaction cannot continue. The other reactant(s) that is not limiting is called the excess reactants.
From the balanced equation, 2 moles of Sr is needed to react with 1 mole of O₂. Thus, if we have 5 moles of each reactant, Sr would be the limiting reactant since for every 1 mole of O₂, there has to be 2 moles of Sr in order for the reaction to proceed. Thus, if we have 5 moles of O₂, we would need 10 moles of Sr.
When we work out the amount of products formed, we look at the number of moles of the limiting reactant. This is because the limiting reactant determines how much is being reacted, while the excess number of moles of the excess reactant will remain unreacted.
For every 2 moles of Sr reacted, 2 moles of SrO would be produced. This means that the mole ratio of Sr to SrO is 1:1. Thus, since 5 moles of Sr has been reacted, 5 moles of the product (SrO) would be produced.
Answer:
The time taken for the cross mark to disappear decreases steadily down the column.
Explanation:
Now if we look at the data provided, we will discover that the volume of the HCl was held constant while the volume of the thiosulphate was increased steadily and the volume of water decreased steadily.
Recall that a system is more concentrated when it contains less volume of water and more volume of reactants. Hence as the volume of water in the system is being reduced, the concentration of reactants is increased.
It has been established that an increase in the concentration of reactants lead to an increase in the rate of reaction. The disappearance of the cross shows the completion of the reaction between HCl and thiosulphate. The faster or slower the cross disappears, the faster or slower the rate of reaction.
Since increase in concentration of reactants increases the rate of reaction, it is observed that as the volume of the thiosulphate increases (reactant concentration increases) the cross disappears faster (rate of reactant increases). Hence as the volume of thiosulphate increases, it takes a shorter time for the cross to disappear. This implies that the time column in the table (refer to the question) will decrease steadily as the volume of thiosulphate increases.
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Answer:
151 g/mol
Explanation:
In order to solve this problem we need to keep in mind the formula for the <em>boiling point elevation</em>:
Where:
- ΔT is the temperature difference between the boiling point of the solution and that of pure water. 100.37 °C - 100.00 °C = 0.37 °C.
- <em>m</em> is the molarity of the solution
- i is the van't Hoff factor. As the solute is a nonelectrolyte, the factor is 1.
Input the data and <u>calculate </u><em><u>m</u></em>:
- 0.37 °C = 0.51 °C/m * <em>m</em> * 1
We now can <u>calculate the number of moles of the substance</u>, using the <em>definition of molarity</em>:
- molarity = moles of solute / kg of solvent
In this case kg of solvent = 90.0 g / 1000 = 0.090 kg
- 0.72 m = moles / 0.090 kg
Finally we <u>calculate the molar mass</u>, using the <em>number of moles and the mass</em>:
- 9.81 g / 0.065 mol = 151 g/mol
