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iris [78.8K]
3 years ago
10

The compound ncl3 is nitrogen trichloride, but alcl3 is simply aluminum chloride. why

Chemistry
2 answers:
STALIN [3.7K]3 years ago
6 0

\text{NCl}_3 is covalent and therefore named as nitrogen trichloride while \text{AlCl}_3 is ionic and therefore named as aluminium chloride.

Further Explanation:

Chemical compound:

These are formed as result of attraction between molecules and atoms known as chemical bond. Chemical bonds can be formed either due to electron transfer or electron sharing.

Covalent compound:

These compounds result by chemical bonds formed by sharing of electrons. Such compounds are also known as molecular compounds.

Ionic compound:

These compounds are formed as result of ionic bond. Ionic bond makes use of electron transference from metallic atom to non-metallic atom. Ions are formed in this bond formation.

In \text{NCl}_3 , both constituent atoms are non-metals so covalent bond is formed between these atoms. As a result, \text{NCl}_3 is covalent compound and number of atoms is mentioned while writing their names. Therefore \text{NCl}_3 is named as nitrogen trichloride.

But in \text{AlCl}_3 , aluminum is metal and chlorine is non-metal so ionic bond is formed between these atoms and  \text{AlCl}_3 is an ionic compound. While writing names of ionic compounds, number of atoms is not mentioned and therefore   \text{AlCl}_3 is named as aluminum chloride.

Learn more:

  • Identification of ionic bonding: brainly.com/question/1603987
  • What type of bond exists between phosphorus and chlorine? brainly.com/question/81715

Answer details:

Grade: High School

Chapter: Chemical bonding

Subject: Chemistry

Keywords: chemical bond, ionic bond, metallic bond, valence electrons, attraction, cation, anion, metals, atoms, molecules, electrons, positive ions.

AveGali [126]3 years ago
5 0
The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride<span>.
</span><span>The compound AlCl3 is an ionic compound (metal and nonmetal), and therefore does not require prefixes. so AlCl3 is aluminum chloride.
</span><span>
Both of nitrogen and chlorine is nonmetal, but aluminum is metal. Metal with nonmetal will make an ionic compound that doesn't need prefixes.</span>
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HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.6 × 10−3 at 25∘C If 1.0 M HI is placed into
dsp73

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.037 M

<u>Explanation:</u>

We are given:

Initial concentration of HI = 1.0 M

The given chemical equation follows:

                       2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>               1.0

<u>At eqllm:</u>        1.0-2x          x           x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

Kc=1.6\times 10^{-3}

Putting values in above expression, we get:

1.6\times 10^{-3}=\frac{x\times x}{(1.0-2x)^2}\\\\x=-0.043,0.037

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.037 M

Hence, the concentration of hydrogen gas at equilibrium is 0.037 M

6 0
3 years ago
A sample of propane, C3H8, occupies 1.73 mL when the pressure is 320 torr at 30 C. What is the volume at STP
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The volume of the sample of propane at STP is 0.62 mL.

<h3>What is volume?</h3>

Volume is the amount of space that a substance or object occupies.

To calculate the volume of gas at STP, we apply the formula below.

Formula:

  • PV/T = P'V'/T'................. Equation 1

Where:

  • P = Initial pressure of gas
  • V = Initial volume of gas
  • T = Initial temperature of gas
  • P' = Standard pressure (SP)
  • T' = Standard temperature (ST)
  • V' = Volume of gas at STP.

Make V' The subject of the equation

  • V' = PVT'/P'T.............. Equation 2

From the question,

Given:

  • P = 320 torr
  • V = 1.73 mL
  • T = 30 °C = (30+273) K = 303 K
  • P' = 760 torr
  • T' = 273 K

Substitute these values into equation 2

  • V' = (320×1.73×273)/(760×303)
  • V' = 0.62 mL

Hence, the volume of the sample of propane at STP is 0.62 mL.
Learn more about volume here: brainly.com/question/26507715

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