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VARVARA [1.3K]
3 years ago
5

Sample A: 300 mL of 1M sodium chloride

Chemistry
1 answer:
yarga [219]3 years ago
5 0

Answer:

sample B contains the larger density

Explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

C = \frac{moles \ of \ solute, \ mol}{liters \ of \ solvent} \\\\Moles \ of \ solute \ for \ sample \ A = 1 \times 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 \times 0.145 = 0.2175 \ mol

The reacting mass for sample A = 0.3mol x  58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A  = \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L

The density of sample B = \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L

Therefore, sample B contains the larger density

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