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tamaranim1 [39]
3 years ago
5

What is the balanced equation for: Ammonium Carbonate and Magnesium Sulfate react to yield Ammonium Sulfate plus Magnesium Carbo

nate?
Chemistry
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

(NH₄)₂CO₃ (aq) + MgSO₄(aq)  →  (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓  

Explanation:

We determine the reactants:

(NH₄)₂CO₃ → Ammonium carbonate

MgSO₄ → Magnesium sulfate

We determine the products:

(NH₄)₂SO₄ ; MgCO₃

All the salts from carbonates are precipitates:

(NH₄)₂CO₃ (aq) + MgSO₄(aq)  →  (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓  

Ratio is all 1:1. 1 mol of ammonium carbonate reacts to 1 mol of magnessium sulfate in order to produce 1 mol of ammonium sulfate and 1 mol of magnessium carbonate.

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Write the chemical formula for carbon tetrachloride and calcium bromide
aliya0001 [1]
Carbon tetra chloride = CCl4

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8 0
3 years ago
When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
dlinn [17]

Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

8.30^0C=1\times K_f\times 0.579

K_f=14.3^0C/m

Let Mass of solute (KBr) = x g

8.3^0C=1.72\times 14.3\times \frac{xg\times 1000}{119g/mol\times 1450g}

x=58.2g

Thus the mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

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Answer:

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Neutrons are found in the nucleus and separate the other particles so that the strong force can hold the nucleus together. Which
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