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1 year ago

What is osmoregulation

1 answer:

5 0

Given what we know, we can confirm that osmoregulation is the way the system regulates osmotic pressure by maintaining osmotic fluids in the body.

<h3>What is osmoregulation?</h3>

Osmoregulation is the way the system regulates osmotic pressure by maintaining osmotic fluids in the body. For the metabolic reactions of the body to function properly, the concentrations of water and solutes must be within established limits. Osmoregulation is the maintenance of homeostasis in the body in terms of solute and water concentrations.

For animal cells, an isosmotic solution is necessary so that the fluids inside and outside the cell have the same pressure. An important pump for this maintenance is the Na+/K+ ATPase pump via active transport.

Therefore, we can confirm that osmoregulation is the way the system regulates osmotic pressure by maintaining osmotic fluids in the body.

To learn more about osmoregulation visit: brainly.com/question/3454642?referrer=searchResults

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victus00 [196]

Answer:

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Explanation:

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3 years ago

Two students are given cubic boxes, measuring 10 cm on a side. Robert puts a single glass marble with a

Katyanochek1 [597]

Answer:

Both boxes have the same amount of empty space

Explanation:

Given

Cube Box

$Length = 10cm$

Robert:

1 glass marble

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Susan:

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Required

Whose box has more empty space?

First, we need to calculate the volume of the cubic box.

$Volume = Length^3$

Substitute 10cm for Length

$Volume = 10^3$

$Volume = 1000cm^3$

Next, calculate the volume of Robert's glass

Volume is calculated as:

$Volume = \frac{4}{3}\pi r^3$ ---- Volume of a sphere

Where

r = radius

$r = \frac{1}{2} * Diameter$

$Diameter = 10cm$ --- Given

Substitute 10 for diameter

$r = \frac{1}{2} * 10cm$

$r = 5cm$

So:

$Volume = \frac{4}{3}\pi r^3$

$Volume = \frac{4}{3} * \frac{22}{7} * 5^3$

$Volume = \frac{4}{3} * \frac{22}{7} * 125$

$Volume = 523.8cm^3$

Next, we determine the volume of Susan's 1000 glasses

Volume is calculated as:

$Volume = \frac{4}{3}\pi r^3$ ---- Volume of a sphere

Where

r = radius

$r = \frac{1}{2} * Diameter$

$Diameter = 1cm$ --- Given

Substitute 1cm for diameter

$r = \frac{1}{2} * 1cm$

$r = 0.5cm$

Substitute 0.5cm for radius in $Volume = \frac{4}{3}\pi r^3$

$Volume = \frac{4}{3} * \frac{22}{7} * 0.5^3$

$Volume = \frac{4}{3} * \frac{22}{7} * 0.125$

$Volume = 0.5238$

But there are 1000 glasses.

So, the volume of 1000 glasses is:

$Volume = 0.5238 * 1000$

$Volume = 523.8cm^3$

--------------------------------------------------------------------------------------------------------------

For Robert:

$Volume = 523.8cm^3$

For Susan:

$Volume = 523.8cm^3$

Since, they have the same volume.

Both boxes have the same amount of empty space

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2 years ago

If the eyepiece has a magnification of 10x, what would be the total magnification of an image if you were using the lower power

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Mila [183]

Hi!

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Hopefully, this helps! =)

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2 years ago

What is osmoregulation​

What is osmoregulation