Answer:
Explanation:wwwwwwwwwwwwwwwwwwww
Answer:
High explosives do not need to be contained to make their bang. Nitroglycerine, trinitrotoluene, and RDX are high explosives.
Explanation:
First thing, you convert from kPa to Pa. Then, you find the atm value of the Pa you got.
155 kPa = 155 000 Pa
1 atm = 101 325 Pa
x atm = 155 000 Pa
You divide 101 325 over 155 000 and you get about 1.53
So, 155 000 Pa = 1.53 atm.
So, T (temperature) = 25 + 273 = 298
605 kPa = 605 000 Pa
1 atm = 101 325 Pa
x atm = 605 000 Pa
You divide 605 000 over 101 325 and you get about 5.97
So 605 000 Pa = 5.97 atm
So, T = 125 + 273 = 398
P1 * V1/T1 = P2 * V2/T2
1.53 * 1/298 = 5.97 * V2/398
You calculate ad you get V2 = 0.342 L
Hope this Helps :)
Answer:
moles of ammonia produced = 0.28 moles
Explanation:
The reaction is
As per equation, one mole of nitrogen will react with three moles of hydrogen to give two moles of ammonia
So 0.140 moles of nitrogen will react with = 3 X 0.140 moles of Hydrogen
= 0.42 moles of hydrogen molecule.
this will give 2 X 0.140 moles of ammonia = 0.28 moles of ammonia
the moles of ammonia produced = 0.28 moles
Here the nitrogen is limiting reagent.
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