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san4es73 [151]
3 years ago
7

Write the acid-base equilibrium reaction between clo– and h2o. ignore phases.

Chemistry
2 answers:
Andreyy893 years ago
8 0

Acid base equilibrium can be represented as:

ClO⁻ + H₂O ------> HClO + OH⁻

In this ClO⁻ reacts with water molecule that is H₂O, to form HClO and hydroxide ion that is OH⁻.

The equilibrium constant can be represented as:

K_{eq}=\frac{[HClO][OH^{-}]}{[ClO^{^{-}}]}

In equilibrium constant [HClO] represents concentration of HClO, while [OH⁻] represents concentration of [OH⁻] and [ClO⁻] represents concenytration of ClO⁻.


poizon [28]3 years ago
4 0
The reaction equilibrium is:
           ClO⁻ + H₂O ⇄ HClO + OH⁻
Keq = \frac{[HClO][OH^{-} ]}{[ClO^{-} ]}
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tigry1 [53]

Explanation:

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3. The (<u>higher</u>, lower) the altitude, the (<u>colder</u>, warmer) the climate.

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3 0
3 years ago
Help please! Given that the enthalpy of reaction for a system at 298 K is –292 kJ/mol and the entropy for that system is 224 J/m
riadik2000 [5.3K]

Answer:

<h3><em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u>6</u></em><em><u>6</u></em><em><u>,</u></em><em><u> </u></em><em><u>7</u></em><em><u>5</u></em><em><u>1</u></em><em><u> </u></em><em><u>kj</u></em></h3>

Explanation:

hope it helps

3 0
3 years ago
How many moles of NaF are produced in the resction between sodium bromide and calcium fluoride when 550 grams of sodium bromide
bija089 [108]

Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.

Explanation:

From the question, the balanced chemical formula is illustrated below:

2NaBr + CaF2 → 2NaF + CaBr2

From the equation above;

Molecular mass of NaBr = 23 + 80 = 103g/ mol

Molecular mass of CaF2= 40+ (19×2)= 78g/ mol

Molecular mass of NaF = 23+19 = 42g/ mol

From the balanced chemical equation;

2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.

That is, 2 moles of NaBr= 2× 103 = 206g

2moles of NaF = 2×42= 84g

If 206g of NaBr yielded 84g of NaF

Therefore 550g of NaBr will yield Xg of NaF

X= 550×84/206

X= 224.27g of NaF

But 42g = 1 mole of NaF

Therefore 224.27g = X mole of NaF

X= 224.27 ×1/42

X is approximately 5moles.

6 0
3 years ago
24g copper is submerged in water in a graduated cylinder, the total volume increases bu 2.7ml what is the density of copper
Brilliant_brown [7]

Answer:

<h2>8.89 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{24}{2.7}  \\  = 8.88888...

We have the final answer as

<h3>8.89 g/mL</h3>

Hope this helps you

8 0
3 years ago
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6 0
3 years ago
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