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disa [49]
1 year ago
7

In his explanation of the threshold frequency in the photoelectric effect, Einstein reasoned that the absorbed photon must have

a minimum energy to dislodge an electron from the metal surface. This energy is called the work function (Ф) of the metal. What is the longest wavelength of radiation (in nm) that could cause the photoelectric effect in each of these metals:
(a) calcium, Ф=4.60 × 10⁻¹⁹J
Chemistry
1 answer:
astraxan [27]1 year ago
7 0

The wavelength of radiation that could cause the photoelectric effect in calcium is &\lambda=4.32×10^{-7} m

<h3>What is the photoelectric effect?</h3>

The photoelectric effect is a phenomenon that results in electrically charged particles being discharged from or within a substance when it absorbs electromagnetic radiation. When light strikes a metal plate, the action is frequently described as the ejection of electrons from the plate.

For calcium, the wavelength will be

$$\begin{aligned}&\mathrm{E}=4.6^{*} 10^{-19} \mathrm{~J} \\&\mathrm{~h}=6.626^{*} 10^{-34} \mathrm{Js} \\&\mathrm{c}=3^{*} 10^{8} \mathrm{~m} / \mathrm{s} \\&\mathrm{E}=\frac{h c}{\lambda} \\&\lambda=\frac{h c}{E} \\&\lambda=\frac{6.626 * 10^{-34} \mathrm{Js} * 3 * 10^{8} \mathrm{~m} / \mathrm{s}}{4.6 * 10^{-19} \mathrm{~J}} \\&\lambda=4.32^{*} 10^{-7} \mathrm{~m}\end{aligned}$$

The wavelength of radiation that could cause the photoelectric effect in calcium is &\lambda=4.32 ×10^{-7} \mathrm{~m}.

To know more about the photoelectric effect, visit: brainly.com/question/1279581

#SPJ4

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What is the Damkohler number? b) What is the significance of a system with a low Damkohler number?
elena-s [515]

Explanation:

(a)  A number which is dimensionless and provides us an estimate of the degree of conversion which can be achieved in CSTR, that is, continuous stirred tank reactor is known as Damkohler number.

This number is denoted as Da.

Mathematically,     Da = \frac{\text{reaction rate}}{\text{convection rate}}

             Da = \frac{-rA \times V}{Fa_{o}}

Now, for first order system, Da = \frac{-rA \times V}{Fa_{o}}

                        = \frac{k \times CA_{o} \times V}{v \times CA_{o}} = Tk

where,      rA = rate of reaction

                V = volume of reactor

                Fa_{o} = molar flow rate of component A

                 k = rate constant

               CA_{o} = initial concentration of A

                  v = volumetric flow rate of A

                  T = residence time

(b)   Since, from a given Damkohler number we can figure out the possible conversion of CSTR, that is, continuous stirred tank reactor.

So, if we have a low Damkohler number then the system will give us a less conversion formula. As the conversion is as follows.

                       X = \frac{Da}{Da + 1}

Hence, we can conclude that Da \leq 0.1 will give less than 10% conversion as calculated by using above formula.

8 0
3 years ago
Aldol condensation of 2,5-heptanedione yields a mixture of two enone products in a 9:1 ratio. Treatment of the minor product wit
sattari [20]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The diagram of the mechanism of this reaction is shown on the second uploaded image

The structure of the enolate Ion 1 is shown on the third uploaded image

Explanation:

6 0
2 years ago
If 25.8 grams of BaO dissolve in enough water to make a 212 gram solution, what is the percent by mass of the solution?
Scorpion4ik [409]
Mass of solute = 25.8 g

mass solution = 212 g

% =(  mass of solute / mass solution ) x 100

% = ( 25.8 / 212 ) x 100

% = 0.122 x 100

= 12.2 %



6 0
3 years ago
Read 2 more answers
Need help with this question
hichkok12 [17]
What question? Lhh this is hilarious.
4 0
3 years ago
For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.
Anni [7]

Answer:

1 - Salts required  that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - CaSO_3 (Option b) ,BaCrO_4 (Option c) and CaS (Option d)

2 - Salts  that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - Mg(OH)_2 (Option a)

Explanation:

K_s_p values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

  1. CuS {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts CaSO_3 , BaCrO_4 and CaS  have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

K_s_p Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

  2. Zn(OH)_2 dissociates into ions in ratio 1:2 .

Because the ions in the salt Mg(OH)_2 are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

              Salt 2 is matched with option a.

4 0
3 years ago
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