Answer is: A) 124 s.
c₀ = 3 mol/L.
c₁ = 0,700 mol/L.
k = 8,8·10⁻³ 1/M·s.
Integrated second order rate law is: 1/c₁ = 1/c₀ + k·t.
k·t = 1/0,700 - 1/3.
0,0088·t = 1,095.
t = 1,095 ÷ 0,0088.
t = 124 s.
c₀ - <span>initial concentration.
c</span>₁ - <span> concentration at a particular time.
k - </span><span>the rate constant.
t - time.</span>
WATER is wet to make it a more marketable commodity
Answer: False, I believe.
Explanation: If a Hypothesis is proven correct, then another experiment to strengthen that Hypothesis is should be done.
Answer: In an open system the vapor pressure is equal to the outside air pressure.
Explanation:
An open system is a system that is capable of exchanging both matter and energy with its surroundings.
For example, a hot cup of coffee is an open system as the cup is not covered with a lid. Therefore, heat energy from the coffee goes into the surroundings.
Vapor pressure is defined as the ability of a substance to change into vapor state. pressure
Therefore, we can conclude that in an open system the vapor pressure is equal to the outside air pressure.